Consider the following C++ code: int n = 1; // global printl (int x) { cout << x + n; } plus n() { n = n + 2; printl (n); } main () { int n; n = 20; printl (5); n = 40; plus_n(); - cout << n; } What is the output of the program under? b. Static scoping rules

C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter6: Modularity Using Functions
Section6.4: A Case Study: Rectangular To Polar Coordinate Conversion
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Consider the following C++ code:
int n
=
1; // global
printl (int x) {
cout << x + n;
}
plus_n () {
n
= n + 2;
printl (n);
}
main () {
int n;
n =
= 20;
print1 (5);
n
= 40;
plus_n ();
cout << n;
}
What is the output of the program under?
b. Static scoping rules
Transcribed Image Text:Consider the following C++ code: int n = 1; // global printl (int x) { cout << x + n; } plus_n () { n = n + 2; printl (n); } main () { int n; n = = 20; print1 (5); n = 40; plus_n (); cout << n; } What is the output of the program under? b. Static scoping rules
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