Consider the following bivariate function f(z,y) = 4(2-4)2-2y² +3zy where the domain is z, y € R All numerical answers are to be provided as decimal numbers and accurate to 4dp. (Do not use a decimal","!) Where required use the correct algebra syntax. The first partial derivatives of this function are ft- 66 B6 The function has one stationarity points (complete the z, y coordinates). If you think that there is only one stationarity point enter "9999" into the coordinates of Point B. If you think that there is no stationarity point enter "9999" into the coordinates of both points. Point A: (Number Point B(Number Number Number
Consider the following bivariate function f(z,y) = 4(2-4)2-2y² +3zy where the domain is z, y € R All numerical answers are to be provided as decimal numbers and accurate to 4dp. (Do not use a decimal","!) Where required use the correct algebra syntax. The first partial derivatives of this function are ft- 66 B6 The function has one stationarity points (complete the z, y coordinates). If you think that there is only one stationarity point enter "9999" into the coordinates of Point B. If you think that there is no stationarity point enter "9999" into the coordinates of both points. Point A: (Number Point B(Number Number Number
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Point A needed
Kindly solve ASAP in 10 minutes in the order to get positive feedback please show me neat and clean work ASAP
Transcribed Image Text:Consider the following bivariate function
f(z,y) = 4(2-4)2-2y² + 3xy
where the domain is z, y € R.
All numerical answers are to be provided as decimal numbers and accurate to 4dp. (Do not use a decimal ","!)
Where required use the correct algebra syntax.
The first partial derivatives of this function are
f=
AA
The function has one stationarity points (complete the z, y coordinates). If you think that there is only one stationarity point enter "9999" into the coordinates
of Point B. If you think that there is no stationarity point enter "9999" into the coordinates of both points.
Point A: (Number
Point B (Number
Number
Number
The second order partial derivatives are
fay=3
BD
The determinant of the Hessian at Stationarity Point A is: det (HA) = Number
Transcribed Image Text:Point A is a
O Local minimum
O Local maximum
O Global and local minimum
O Global and local maximum
O Saddle point
Evaluating the Hessian matrix across the domain, which of the following is correct?
O The Hessian is positive semi-definite everywhere.
O The Hessian is indefinite everywhere.
O The Hessian is positive definite everywhere.
O The Hessian is negative definite in some regions of the domain and positive definite in others.
O The Hessian is negative definite everywhere.
Which of the following is correct? (multiple correct answers are possible)
The function has a global maximum as, at no point in the function's domain., f(x, y) < f(A).
The function has a global maximum as, at no point in the function's domain, f(x,y) > f(A).
The function has a global minimum as, at no point the function's domain, f(x, y) < f(A).
0
The function has a global optimum (maximum or minimum) as the respective sufficient condition for a local optimum to also be a global optimum,
is met
The function has no global optimum (maximum or minimum).
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