Consider the following assembly language code: LCO: string "answer %d\n" text globl main type main, @function main: pushq %rbp movq %rsp, %rbp subq $16, %rsp movl $12,-8(%rbp) movl $3, -4(%rbp) movi $0, -16(%rbp) movl -8(%rbp), %eax xorl 4(%rbp), %eax movi %eax, -12(%rbp) jmp 12 13: movi -12(%rbp), %eax andl $1, %eax addl %eax, -16(%rbp)
Consider the following assembly language code: LCO: string "answer %d\n" text globl main type main, @function main: pushq %rbp movq %rsp, %rbp subq $16, %rsp movl $12,-8(%rbp) movl $3, -4(%rbp) movi $0, -16(%rbp) movl -8(%rbp), %eax xorl 4(%rbp), %eax movi %eax, -12(%rbp) jmp 12 13: movi -12(%rbp), %eax andl $1, %eax addl %eax, -16(%rbp)
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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dont post irrelevant answers and copied answers
else report the answer for sure
dont answer without any knowledge
![Consider the following assembly language code:
LCO:
string "answer %d\n"
text
globi main
type main, @function
main:
pushq %rbp
movq %rsp, %rbp
subq $16, %rsp
movl $12, -8(%rbp)
movl $3, -4(%rbp)
movl $0, -16(%rbp)
movi -8(%rbp), %eax
-4(%rbp), %eax
movi %eax, -12(%rbp)
xorl
jmp 12
L3:
movl -12(%rbp), %eax
andl $1, %eax
addi %eax, -16(%rbp)
-12(%rbp)
sarl
L2:
cmpl $0, -12(%rbp)
jne
13
movi -16(%rbp), %eax
movl %eax, %esi
leaq LCO(%rip), %rdi
movl $0, %eax
call
printf@PLT
movi $0, %eax
leave
ret
This code came from skeleton C file below after optimizing with 00. This means "gcc -00 -5 fno-
asynchronous-unwind-tables" command was used to convert C File into assembly file. (The last option was
used to disable cfi directives)
Complete the C code given below using the provided assembly code
One approach may be to ignore the skeleton file and create an equivalent C code from the assembly
code, and then rewrite the code to fit the skeleton file.
int main(){
int a =
b 3:
int count
for(int e = a
b; e != o; e=e
1){
count + (c
1);
}
printf("answer %d\n", count);
return o;](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F363d6d07-cdba-4034-99aa-699a6a50c3b9%2F487df512-5926-40f2-84c2-16455c8be606%2Fz3lqi1j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the following assembly language code:
LCO:
string "answer %d\n"
text
globi main
type main, @function
main:
pushq %rbp
movq %rsp, %rbp
subq $16, %rsp
movl $12, -8(%rbp)
movl $3, -4(%rbp)
movl $0, -16(%rbp)
movi -8(%rbp), %eax
-4(%rbp), %eax
movi %eax, -12(%rbp)
xorl
jmp 12
L3:
movl -12(%rbp), %eax
andl $1, %eax
addi %eax, -16(%rbp)
-12(%rbp)
sarl
L2:
cmpl $0, -12(%rbp)
jne
13
movi -16(%rbp), %eax
movl %eax, %esi
leaq LCO(%rip), %rdi
movl $0, %eax
call
printf@PLT
movi $0, %eax
leave
ret
This code came from skeleton C file below after optimizing with 00. This means "gcc -00 -5 fno-
asynchronous-unwind-tables" command was used to convert C File into assembly file. (The last option was
used to disable cfi directives)
Complete the C code given below using the provided assembly code
One approach may be to ignore the skeleton file and create an equivalent C code from the assembly
code, and then rewrite the code to fit the skeleton file.
int main(){
int a =
b 3:
int count
for(int e = a
b; e != o; e=e
1){
count + (c
1);
}
printf("answer %d\n", count);
return o;
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