Consider the following assembly code: loop: .L4: movl jmp .L2: .L3: cmpl jle addl addl cmpl jl .L5: } cmpl sete cmpl setl testb jne movl ret $0, %eax .L2 %esi, %edi .L3 $1, %eax %ecx, %esi } return %edx, %esi .L4 %esi, %edi %cl %edx, %esi %d1 %dl, %cl The preceding code was generated by compiling C code that had the following overall form: .L5 $-1, %eax int loop(int a, int b, int c, int d) { int e; int f = for (e= if ( e< e += Your task is to fill in the missing parts of the C code to get a program equivalent to the generated assembly code.
Consider the following assembly code: loop: .L4: movl jmp .L2: .L3: cmpl jle addl addl cmpl jl .L5: } cmpl sete cmpl setl testb jne movl ret $0, %eax .L2 %esi, %edi .L3 $1, %eax %ecx, %esi } return %edx, %esi .L4 %esi, %edi %cl %edx, %esi %d1 %dl, %cl The preceding code was generated by compiling C code that had the following overall form: .L5 $-1, %eax int loop(int a, int b, int c, int d) { int e; int f = for (e= if ( e< e += Your task is to fill in the missing parts of the C code to get a program equivalent to the generated assembly code.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Please Help ASAP!!!
![Consider the following assembly code:
loop:
.L4:
.L2:
.L3:
.L5:
movl
jmp
cmp1
jle
addl
addl
}
cmpl
jl
cmp1
sete
cmpl
setl
testb
jne
movl
ret
$0, %eax
.L2
%esi, %edi
.L3
$1, %eax
%ecx, %esi
}
return
%edx, %esi
.L4
The preceding code was generated by compiling C code that had the following overall form:
%esi, %edi
%cl
%edx, %esi
%d1
%d1, %cl
.L5
$-1, %eax
int loop(int a, int b, int c, int d) {
int e;
int f =
for (e=
if (
; e<
e +=
Your task is to fill in the missing parts of the C code to get a program equivalent to the generated assembly code.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd5655175-49d2-4db6-a7fd-785d70a02cda%2F9d3fcd10-7f4b-43e1-8a90-93469b26e0e8%2Fy0fqbsl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the following assembly code:
loop:
.L4:
.L2:
.L3:
.L5:
movl
jmp
cmp1
jle
addl
addl
}
cmpl
jl
cmp1
sete
cmpl
setl
testb
jne
movl
ret
$0, %eax
.L2
%esi, %edi
.L3
$1, %eax
%ecx, %esi
}
return
%edx, %esi
.L4
The preceding code was generated by compiling C code that had the following overall form:
%esi, %edi
%cl
%edx, %esi
%d1
%d1, %cl
.L5
$-1, %eax
int loop(int a, int b, int c, int d) {
int e;
int f =
for (e=
if (
; e<
e +=
Your task is to fill in the missing parts of the C code to get a program equivalent to the generated assembly code.
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