Consider the following air-conditioning system design which involves a refrigeration process ('cooling coil unit') and a mixing process ('mixing box'). Cooling Unit 2 Mixing Box mai T, Ø1 w2 T2 Ø2 |Mcoolant Tcoolant,in 3 maz T3 03 Condensate Cooling Coil Coolant Return Air For steady state operation of the cooling coil unit at 1 atm, determine the following: 42. the mass balance for the dry air; a) mai < ma2 b) ma1 = ma2 = ma c) ma1 - maz = Ma d) mai > ma2 %3D 43. the mass balance for the water; a) my1 = my2 – MH20 b) my1 = my2 = MH20 c) my1 + mv2 = MH20 d) my1 = my2 + mµ20 44. the energy rate balance; a) Qcooling = ma[(ha1 + w,hg1) – (haz + wzhg2) – mu20hu20o] b) Čcooling = m,[(ha1 + w,hg1) + (ha2 + wzhg2)] – mu20hu20 c) Čcooling = Mal(ha1 + w,hgs) – (haz + wzhgz)] – mH20hH20 d) Čcooling = mal(hai + wihg1) – (haz + wzhg2)] – (@1 – wz)hrz %3D

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Consider the following air-conditioning system design which involves a refrigeration process ('cooling
coil unit') and a mixing process ('mixing box').
1
Cooling Unit
2
Mixing Box
4
ma1 T1 Ø1
w2 T2 02
T, Ø4
Mcoolant
Tcoolant,in
3
ma3 T3 Ø3
Condensate
Cooling Coil
Coolant
Return Air
For steady state operation of the cooling coil unit at 1 atm, determine the following:
42. the mass balance for the dry air;
a) ma1 < ma2
b) ma1 = ma2 = ṁa
c) ma1 – ma2 = Ma
d) ma1 > ma2
43. the mass balance for the water;
a)
my1 = my2 – MH20
b)
my1 = My2 = MH20
c)
d)
my1 + my2 = ṁH20
my1 = my2 + MH20
44. the energy rate balance;
a) Qcooling = ħa[(hạ1 + w,hg1) – (haz + wzhg2) – Mu20hH20]
b) Qcooling = ma[(ha1 + w, hg1) + (haz + wzhg2)] – mH20hH20
c) Qcooling = mal(ha1 + w,hg1) – (ha2 + wzhg2)] – mµ20hH20
d) Čcooling = Ma[(hai + wihg1) – (haz + @zhg2)] – (@1 – wz)hrz
%3D
%3D
Transcribed Image Text:Consider the following air-conditioning system design which involves a refrigeration process ('cooling coil unit') and a mixing process ('mixing box'). 1 Cooling Unit 2 Mixing Box 4 ma1 T1 Ø1 w2 T2 02 T, Ø4 Mcoolant Tcoolant,in 3 ma3 T3 Ø3 Condensate Cooling Coil Coolant Return Air For steady state operation of the cooling coil unit at 1 atm, determine the following: 42. the mass balance for the dry air; a) ma1 < ma2 b) ma1 = ma2 = ṁa c) ma1 – ma2 = Ma d) ma1 > ma2 43. the mass balance for the water; a) my1 = my2 – MH20 b) my1 = My2 = MH20 c) d) my1 + my2 = ṁH20 my1 = my2 + MH20 44. the energy rate balance; a) Qcooling = ħa[(hạ1 + w,hg1) – (haz + wzhg2) – Mu20hH20] b) Qcooling = ma[(ha1 + w, hg1) + (haz + wzhg2)] – mH20hH20 c) Qcooling = mal(ha1 + w,hg1) – (ha2 + wzhg2)] – mµ20hH20 d) Čcooling = Ma[(hai + wihg1) – (haz + @zhg2)] – (@1 – wz)hrz %3D %3D
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