Consider the following acid/base reaction. Will 1 or 2 act as the acid? Will the equilibrium favor the reactants or the products? HS. 1 NH₂₂ + Reactants 2 A) 1 will act as the acid and the equilibrium will favor the reactants. B) 2 will act as the acid and the equilibrium will favor the reactants. C) 1 will act as the acid and the equilibrium will favor the products. D) 2 will act as the acid and the equilibrium will favor the products. E) None of the above. Products
Consider the following acid/base reaction. Will 1 or 2 act as the acid? Will the equilibrium favor the reactants or the products? HS. 1 NH₂₂ + Reactants 2 A) 1 will act as the acid and the equilibrium will favor the reactants. B) 2 will act as the acid and the equilibrium will favor the reactants. C) 1 will act as the acid and the equilibrium will favor the products. D) 2 will act as the acid and the equilibrium will favor the products. E) None of the above. Products
Chemistry
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
- t-Butylthiol (2)
**Reaction Equation:**
\[
\text{Cyclohexylamine (1) + t-Butylthiol (2) ⇌ Products}
\]
**Choices:**
A) 1 will act as the acid and the equilibrium will favor the reactants.
B) 2 will act as the acid and the equilibrium will favor the reactants.
C) 1 will act as the acid and the equilibrium will favor the products.
D) 2 will act as the acid and the equilibrium will favor the products.
E) None of the above.
**Explanation:**
To determine which compound will act as the acid, we must consider the relative acidity and basicity of the reactants. Cyclohexylamine (1) is a weak base, and t-Butylthiol (2) has a slightly acidic thiol group. Therefore, t-Butylthiol (2) is more likely to donate a proton (act as the acid).
**Solution:**
Based on the nature of the reactants:
- 2 (t-Butylthiol) will act as the acid.
- The equilibrium will be investigated to determine if it favors the reactants or products based on their stability.
Given this information, evaluate the options to see which aligns with this understanding.
For more detailed analysis and theoretical background, please refer to relevant chemistry educational resources.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F47f16b03-5eea-43fc-9b52-7dcc57452af9%2F1a3e617d-7595-4e3c-b089-cb4723946957%2Fxgoryvi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Acid-Base Reaction Analysis**
**Consider the following acid/base reaction. Will 1 or 2 act as the acid? Will the equilibrium favor the reactants or the products?**
**Chemical Reaction:**
A chemical equation is provided with two reactants and reversible reaction arrows indicating equilibrium between reactants and products. The chemical structures of the reactants are as follows:
1. Cyclohexylamine (a cyclohexane ring with an amine group, NH2, attached).
2. t-Butylthiol (a tert-butyl group with a thiol group, HS, attached).
Representing the reaction:
**Reactants:**
- Cyclohexylamine (1)
- t-Butylthiol (2)
**Reaction Equation:**
\[
\text{Cyclohexylamine (1) + t-Butylthiol (2) ⇌ Products}
\]
**Choices:**
A) 1 will act as the acid and the equilibrium will favor the reactants.
B) 2 will act as the acid and the equilibrium will favor the reactants.
C) 1 will act as the acid and the equilibrium will favor the products.
D) 2 will act as the acid and the equilibrium will favor the products.
E) None of the above.
**Explanation:**
To determine which compound will act as the acid, we must consider the relative acidity and basicity of the reactants. Cyclohexylamine (1) is a weak base, and t-Butylthiol (2) has a slightly acidic thiol group. Therefore, t-Butylthiol (2) is more likely to donate a proton (act as the acid).
**Solution:**
Based on the nature of the reactants:
- 2 (t-Butylthiol) will act as the acid.
- The equilibrium will be investigated to determine if it favors the reactants or products based on their stability.
Given this information, evaluate the options to see which aligns with this understanding.
For more detailed analysis and theoretical background, please refer to relevant chemistry educational resources.
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