Consider the following 3x3 contingency table: AA Aa aa Low fitness 39 8 2 Average fitness 11 18 10 High fitness 20 33 You use these data to test the null hypothesis that the genotypes at the A-locus are independent of levels of fitness. Here, fitness is defined as the ability to live and produce lots of offspring. Using these data, the chi-squared statistic is The dregees of freedom are If the correspnding critical value is 9.487729, you would the null hypothesis. For the chi-squared statistic, please carry your answer to two decimal places and follow normal rounding procedures (5 and below, round down; >5 round up). For the degrees of freedom, provide a numeric values that is an integer (e.g. 1, 2, 3, 4, 5, 6, etc.).
Consider the following 3x3 contingency table: AA Aa aa Low fitness 39 8 2 Average fitness 11 18 10 High fitness 20 33 You use these data to test the null hypothesis that the genotypes at the A-locus are independent of levels of fitness. Here, fitness is defined as the ability to live and produce lots of offspring. Using these data, the chi-squared statistic is The dregees of freedom are If the correspnding critical value is 9.487729, you would the null hypothesis. For the chi-squared statistic, please carry your answer to two decimal places and follow normal rounding procedures (5 and below, round down; >5 round up). For the degrees of freedom, provide a numeric values that is an integer (e.g. 1, 2, 3, 4, 5, 6, etc.).
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Consider the following 3x3 contingency table:
AA
Aa
aa
Low fitness
39
8
2
Average fitness
11
18
10
High fitness
3
20
33
You use these data to test the null hypothesis that the genotypes at the A-locus are
independent of levels of fitness. Here, fitness is defined as the ability to live and produce
lots of offspring. Using these data, the chi-squared statistic is
The
dregees of freedom are
If the correspnding critical value is 9.487729,
you would
the null hypothesis. For the chi-squared statistic, please carry
your answer to two decimal places and follow normal rounding procedures (5 and below,
round down; >5 round up). For the degrees of freedom, provide a numeric values that is an
integer (e.g. 1, 2, 3, 4, 5, 6, etc.).
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