Consider the following 3x3 contingency table: AA Aa aa Low fitness 39 8 2 Average fitness 11 18 10 High fitness 20 33 You use these data to test the null hypothesis that the genotypes at the A-locus are independent of levels of fitness. Here, fitness is defined as the ability to live and produce lots of offspring. Using these data, the chi-squared statistic is The dregees of freedom are If the correspnding critical value is 9.487729, you would the null hypothesis. For the chi-squared statistic, please carry your answer to two decimal places and follow normal rounding procedures (5 and below, round down; >5 round up). For the degrees of freedom, provide a numeric values that is an integer (e.g. 1, 2, 3, 4, 5, 6, etc.).

Q: The answer is not shown for the 2

A: Left end sum=sum of areas of the rectangles      =7X10+9.8X10+13.2X10+18.1X10+20.5X10      =68.6X10…

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A: We can answer the question as below.

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A: Hi thanks you for posting this question  , since you have posted multiple subparts as per our policy…

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Q: the question didnt have any other information would you be able to solve part d

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A:

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Q: could you maybe elaborate a bit more and how you find these answers? especially with b?

A:

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A:

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