Consider the five slit problem outlined in the previous question. If the wavelength of light is 500 nm and the slits are separated by 2.50 × 10-° m, calculate the distance between the central maximum and the first dark spot on a screen that is 1.00 m away. Assume the small angle approximation applies.
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![Consider the five slit problem outlined in the previous question. If the wavelength of light is 500
nm and the slits are separated by 2.50 × 10–6 m, calculate the distance between the central
maximum and the first dark spot on a screen that is 1.00 m away. Assume the small angle
approximation applies.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F224af06f-eeea-4b99-8c86-0f25ebb24952%2F7e613354-5613-478d-b2c0-cda5f23f7894%2Ffrq7zu4_processed.png&w=3840&q=75)
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- Need only handwritten solution only (not typed one).(a) Find the angle ? locating the first minimum in the Fraunhofer diffraction pattern of a single slit of width 0.212 mm, using light of wavelength 594 nm. (b) Find the angle locating the second minimum.A beam of 650 nm light is directed upon two thin slits that are separated by a distance of 0.750 mm. At what angle in degrees does the 3rd order minima occur as measured relative to the principle axis? Only enter a number rounded to 3 decimal places.
- Chapter 36, Problem 017 (a) Find the equation of a at which intensity extrema for single-slit diffraction occur (Im - is maximum). What are the (b) smallest a and (c) associated m, the (d) second smallest a and (e) associated m, and the (f) third smallest a and (g) associated m? (Note: To find values of a satisfying this conditiion, plot the curve y = tan a and the straight line y = a and then find their intersections, or use a calculator to find an appropriate value of a by trial and error. Next, from a = (m+1/2)x, determine the values of m associated with the maxima in the single-slit pattern. These m values are not integers because secondary maxima do not lle exactly halfway between minima.) (a) = 0 2 Edit •1 (b) a = Number Units 2 Units (c) m = Number *3 Units (d) a = Number *4 Units (e) m = Number Units (f) a = Number Units (g) m = NumberTwo slits are illuminated by a monochromatic plane wave of wavelength k. The slits have a width a=3k, and the distance between them is d=9k. (a) Determine if there are any interference maxima that are missing from the two-slit interference pattern because the minimum of the diffraction occurs in the same direction. Find all angles that lead to such missing orders. (b) Calculate the intensity of the first two-slit constructive interference fringe (|m|=1) relative to I(1), the intensity of the central peak.Please asap
- Pls write clearlyConsider the following. (a) Find the angle ? locating the first minimum in the Fraunhofer diffraction pattern of a single slit of width 0.182 mm, using light of wavelength 581 nm.(b) Find the angle locating the second minimum.(a) How far from some grains of red sand must you be so that you are just at the limit of resolving the grains if your pupil diameter is 3mm, the grains are spherical with radius 50μm, and the light from the gains has wavelength 650nm? (b) If the grains were blue and the light from them had wavelength 400nm instead, would the answer to (a) be larger or smaller? (c) Now let's say you are a superhero and you had x-ray vision, so you could see light that had a wavelength of 0.1nm instead. Now how far could you be from the gains of sand to just be at the limit to distinguish one grain of sand from another? (with the same pupil diameter). (assume you're on the beach and there's plenty of light from many frequencies bouncing off the sand, and when you turn on your x-ray vision you aren't bothered by all the other frequencies around).
- Consider the following. (a) Find the angle (theta) locating the first minimum in the Fraunhofer diffraction pattern of a single slit of width 0.210 mm, using light of wavelength 555 nm.(b) Find the angle locating the second minimum.A monochromatic source of light of wavelength λ, is incident on a slit of width a. Obtain an expression to represent the angle of the 4th diffraction minimum. Hint: Think about Huygens construction with the single slit divided into four equal length sections acting as sources of secondary waves. Write down a general expression for the nth minimum angle. If λ =500 nm, a = 4 μm, determine the angle of the 2nd minimum.The limit to the eye's acuity is actually related to diffraction by the pupil. What is the angle between two just-resolvable points of light for a 2.75 mm diameter pupil, assuming the average wavelength of 539 nm? angle between two points of light: Take the result to be the practical limit for the eye. What is the greatest possible distance a car can be from a person if he or she can resolve its two headlights, given they are 1.40 m apart? greatest distance at which headlights can be distinguished: m What is the distance between two just-resolvable points held at an arm's length (0.900 m) from a person's eye? distance between two points 0.900 m from a person's eye: m