Consider the figure shown below. Find thedeflection (in mm correctly up to two decimalplaces) at the free end due to the self-weight ofthe member and the applied loading P = 9.9%3DN. The weight density per unit length of themember, y = 2 N/m. Take length L of the bar = 2m, Cross-section area A = 10 mm?, and Young's%3D%3Dmodulus E = 68 GPa.%3D

The deflection due to self-weight is given by, δ1=γL22E ...1 The deflection due to…

Consider the figure shown below. Find the deflection (in mm correctly up to two decimal places) at the free end due to the self-weight of the member and the applied loading P = 9.9 N. The weight density per unit length of the member, y = 2 N/m. Take length L of the bar = 2 m, Cross-section area A = 10 mm2, and Young's modulus E = 68 GPa. %3D

Consider the figure shown below. Find the deflection (in mm correctly up to two decimal places) at the free end due to the self-weight of the member and the applied loading P = 9.9 N. The weight density per unit length of the member, y = 2 N/m. Take length L of the bar = 2 m, Cross-section area A = 10 mm2, and Young's modulus E = 68 GPa. %3D

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.

Question

Consider the figure shown below. Find the
deflection (in mm correctly up to two decimal
places) at the free end due to the self-weight of
the member and the applied loading P = 9.9
%3D
N. The weight density per unit length of the
member, y = 2 N/m. Take length L of the bar = 2
m, Cross-section area A = 10 mm?, and Young's
%3D
%3D
modulus E = 68 GPa.
%3D

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