Consider the figure below. qa (a) Using the symmetry of the arrangement, determine the direction of the force on q in the figure above, given that q, = 9, = -7.50 µC and q. = 9 = +7.50 µC. toward the top of the page V (b) Calculate the magnitude of the force in newtons on the charge q, given that the square is 10.0 cm on a side and q = 3.50 µC. 27.0005 X N
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- signment valu A pair of parallel conducting plates are given charges of equal magnitude but opposite sign to create a uniform electric field with magnitude 26 N/C. A rectangular surface with dimensions 4.6 cm x 2.2 cm is located in the gap between the parallel plates. Part (a) N-m²/C What is the magnitude of the electric flux, in newton squared meters per coulomb, through the rectangular surface if it is parallel to the charged plates? |DE| = || sin() cotan() cos() tan() 8 9 HOME Grade Summary Deductions Potential Submissions 0% 100% Attempt(s) Remaining: 3 asin() acos(). E^^4 5 6 atan() acotan() sinh() cosh() tanh() cotanh() O Degrees 4% Deduction per Attempt detailed view 12 3 + - 0 END Radians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Submission(s) Remaining Hints: 4% deduction per hint. Hints remaining: 1 Feedback: 5% deduction per feedback. Part (b) What is the magnitude of the electric flux, in newton squared meters per coulomb, through the rectangular surface if it…The figure below shows a dipole. If the positive particle has a charge of 36.9 mC and the particles are 2.62 mm apart, what is the electric field at point A located 2.00 mm above the dipole's midpoint? (Express your answer in vector form.)A uniform spherical charge distribution (as shown in the figure below) has a total charge of 63.3 mC and radiusR = 19.0 cm. Find the electric force exerted on an electron placed at r = 0, 9.5 cm, 19.0 cm, and 28.5 cm. (Assume the positive direction is radially outward. Indicate the direction with the sign of your answer.) r = 0 F = N r = 9.5 cm F = r = 19.0 cm F = N r = 28.5 cm F = N *R メ 9.
- Case II. 9a9b = +7.5 µC and qc = 9d=-7.5 μC. Fnet qa = qc N I I I I I qb a' (d) In your notebook, draw the forces on q due to qal qb' qc and qd. Or use the result of of Homework: Charges on a Square Free Body Diagram. (e) Due to symmetry the direction of the net force is qd Hint: For each force draw the x and y components. Some will add and some will cancel. (f) Calculate the magnitude of the force on the charge q, given that the square is 10.0 cm on a side and q = 2.2 μC. XNeed this with explanationI need last part
- The figure below shows a dipole. If the positive particle has a charge of 35.9 mC and the particles are 2.88 mm apart, what is the electric field at point A located 2.00 mm above the dipole's midpoint? (Express your answer in vector form.) 7 = N/C A d/2 V d/2A charge of Q is distributed as a quarter circle of a radius R. Lambda(theta)= lambda 0 sin theta provides the linear charge density where theta = 0 degrees along the positive x-axis. How would you find the constant of lambda in terms of Q and R, and what would the magnitude of the electric field be equal to at the center point?Needs Complete handwritten solution with 100 % accuracy. Don't use chat gpt or ai i definitely upvote you.
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