Consider the figure below. P M A B Given: mLA = mLD, AP = DQ, AB = BC = CD Prove: BM = CM a. Complete the following two-column proof. Statements Reasons 1. mLA = m2D 1. Given 2. AP = DQ, AB = BC = CD 2. Given 3. 3. Segment Addition Postulate 4. AB + BC = DB 4. 5. 5. Transitive Property 6. △ CAP 열스 BDQ 6. 7. |7. СРСТС 8. BM = CM 8. b. Prove BM = CM by applying properties of transformations. Justify your steps.

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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6.
Practice
CRM 2.1 - Lesson 14
Consider the figure below.
M
A
B
C
Given: mLA = mzD, AP = DQ, AB = BC = CD
Prove: BM = CM
a. Complete the following two-column proof.
Statements
Reasons
1. mLA = mzD
1. Given
2. AP = DQ, AB = BC = CD
2. Given
3.
3. Segment Addition Postulate
4. AB + BC = DB
4.
5.
5. Transitive Property
6. A CAP =A BDQ
6.
7.
7. СРСТС
8. BM = CM
8.
b.
Prove BM = CM by applying properties of
transformations. Justify your steps.
Transcribed Image Text:6. Practice CRM 2.1 - Lesson 14 Consider the figure below. M A B C Given: mLA = mzD, AP = DQ, AB = BC = CD Prove: BM = CM a. Complete the following two-column proof. Statements Reasons 1. mLA = mzD 1. Given 2. AP = DQ, AB = BC = CD 2. Given 3. 3. Segment Addition Postulate 4. AB + BC = DB 4. 5. 5. Transitive Property 6. A CAP =A BDQ 6. 7. 7. СРСТС 8. BM = CM 8. b. Prove BM = CM by applying properties of transformations. Justify your steps.
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