Consider the equilibrium system described by the chemical reaction below. If 8.98 x 10-4 moles of KOH(aq), 8.98 x 10-4 moles of HCN (aq), and 0.0500 moles of KCN (aq) are present in a 1.00 L aqueous solution at equilibrium at 298 K, what is the value of K of the reaction at this temperature? KCN(aq) + H2O(l) = KOH(aq) + HCN(aq) 1
Consider the equilibrium system described by the chemical reaction below. If 8.98 x 10-4 moles of KOH(aq), 8.98 x 10-4 moles of HCN (aq), and 0.0500 moles of KCN (aq) are present in a 1.00 L aqueous solution at equilibrium at 298 K, what is the value of K of the reaction at this temperature? KCN(aq) + H2O(l) = KOH(aq) + HCN(aq) 1
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
Question
![9:58
K =
Consider the equilibrium system described by
the chemical reaction below. If 8.98 x 10-4
moles of KOH(aq), 8.98 x 10-4 moles of
HCN (aq), and 0.0500 moles of KCN (aq) are
present in a 1.00 L aqueous solution at
equilibrium at 298 K, what is the value of K of
the reaction at this temperature?
KCN(aq) + H2O(I) = KOH(aq) + HCN(aq)
[8.98 x 10-4]
Question 9 of 10
1.80 x 10-²
[0.0500]
1.61 x 10-5
1
[1.80 x 10-²]
Submit
Tap here or pull up for additional resources
RESET
[8.06 x 10-7]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8b570b0f-6e1b-46f1-92cb-002d89189618%2Fce2dbe2b-07ac-4f9b-b513-b8e08fe1f65a%2Faxv4akf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:9:58
K =
Consider the equilibrium system described by
the chemical reaction below. If 8.98 x 10-4
moles of KOH(aq), 8.98 x 10-4 moles of
HCN (aq), and 0.0500 moles of KCN (aq) are
present in a 1.00 L aqueous solution at
equilibrium at 298 K, what is the value of K of
the reaction at this temperature?
KCN(aq) + H2O(I) = KOH(aq) + HCN(aq)
[8.98 x 10-4]
Question 9 of 10
1.80 x 10-²
[0.0500]
1.61 x 10-5
1
[1.80 x 10-²]
Submit
Tap here or pull up for additional resources
RESET
[8.06 x 10-7]
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