It said my answers were wrong, someone help! eb 19[1.37 x 10-²]Consider the equilibrium system described by the chemical reactionbelow. At equilibrium, a 3.0 L reaction vessel contained a mixture of1.37 x 10-2 M HI, 6.47 x 10-3 M H₂, and 5.94 x 10-4 M 1₂ at 740 K.What are the values of Kc and Kp for the reaction at thistemperature?2[5.94 x 10-][6.47 x 10-³]Based on the given data, set up the expression for Kc. Each reaction participantmust be represented by one tile. Do not combine terms.[1.37 x 10-²]²1Once the expression is constructed, solve for Kc. Complete Parts 1-2 beforesubmitting your answer.Kc=Question 18 of 41H₂(g) + 2(g) 2 HI(g)[5.94 x 10-4][6.47 x 10-³12[6.47 x 10-³] [5.94 x 10-4][1.37 x 10-²][4.57 x 10-³][5.94 x 10-4]22[2.16 x 10-³]3.56 x 10³48.8[2.31 x 10-4]NEXT >2.81 x 10-42[1.37 x 10-²]48.8RESET2[6.47 x 10-³]2.05 x 10-²LTE 46%Submi

Answered: Consider the equilibrium system…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Question

It said my answers were wrong, someone help!

eb 19
[1.37 x 10-²]
Consider the equilibrium system described by the chemical reaction
below. At equilibrium, a 3.0 L reaction vessel contained a mixture of
1.37 x 10-2 M HI, 6.47 x 10-3 M H₂, and 5.94 x 10-4 M 1₂ at 740 K.
What are the values of Kc and Kp for the reaction at this
temperature?
2[5.94 x 10-]
[6.47 x 10-³]
Based on the given data, set up the expression for Kc. Each reaction participant
must be represented by one tile. Do not combine terms.
[1.37 x 10-²]²
1
Once the expression is constructed, solve for Kc. Complete Parts 1-2 before
submitting your answer.
Kc
=
Question 18 of 41
H₂(g) + 2(g) 2 HI(g)
[5.94 x 10-4]
[6.47 x 10-³12
[6.47 x 10-³] [5.94 x 10-4]
[1.37 x 10-²]
[4.57 x 10-³]
[5.94 x 10-4]2
2
[2.16 x 10-³]
3.56 x 10³
48.8
[2.31 x 10-4]
NEXT >
2.81 x 10-4
2[1.37 x 10-²]
48.8
RESET
2[6.47 x 10-³]
2.05 x 10-²
LTE 46%
Submi

Expert Solution

Step 1

Rules for writing Equilibrium constant expression for an equilibrium reaction :

Equilibrium constant is the product of the molar concentrations of the products, each raised to the power equal to a stoichiometric coefficient divided by the product of the molar concentrations of the reactant each raised to the power equal to its stoichiometric coefficient .

& the most important convention to be kept in mind is that the active mass of a pure solid or pure liquid is considered to be constant.

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions