Consider the equation хд,и — удуи — -и with the initial condition: u(x,y) : = 2 on the circle {(x,y) : x² + y² = 1}. Show that this PDE does not have any solution near the point (- , ,2).

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Consider the equation
хд,и — удуи —D —и
with the initial condition:
u(x, y) = 2 on the circle {(x, y) : x² + y? = 1}.
Show that this PDE does not have any solution near the point (- , ,2).
Transcribed Image Text:Consider the equation хд,и — удуи —D —и with the initial condition: u(x, y) = 2 on the circle {(x, y) : x² + y? = 1}. Show that this PDE does not have any solution near the point (- , ,2).
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