Consider the equation 2y 32(8x² - y) dx + x x) dy 16x dy = 0. Find an integrating factor u(x) (so a function of x alone). u(x) = help (formulas) Now once you have an integrating factor, you can solve the equation as an exact equation. An explicit solution can be found, that is, one of the form y = y(x). Find an explicit solution that solves y(1) = 5. y(x) = ☐ help (formulas) Book: Section 1.8 of Notes on Diffy Qs
Consider the equation 2y 32(8x² - y) dx + x x) dy 16x dy = 0. Find an integrating factor u(x) (so a function of x alone). u(x) = help (formulas) Now once you have an integrating factor, you can solve the equation as an exact equation. An explicit solution can be found, that is, one of the form y = y(x). Find an explicit solution that solves y(1) = 5. y(x) = ☐ help (formulas) Book: Section 1.8 of Notes on Diffy Qs
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question

Transcribed Image Text:Consider the equation
2y
32(8x² - y) dx +
x
x) dy
16x dy = 0.
Find an integrating factor u(x) (so a function of x alone).
u(x)
=
help (formulas)
Now once you have an integrating factor, you can solve the equation as an exact equation. An explicit solution can
be found, that is, one of the form y = y(x). Find an explicit solution that solves y(1) = 5.
y(x) = ☐ help (formulas)
Book: Section 1.8 of Notes on Diffy Qs
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