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Consider the differential equation zy" – v = (1) Making the changes of variable * = e', y = u(t)e 2* in the differential equation (1), we obtain the differential equation, u depending on t, u" – 6u' – bu = 0. The solution of the differential equation (1), depending on the parameter t, with constant c, and C2, is given by: a) { 2(t) y(t) ´z(t) et et (c1 cos(tv/15) + c2 sen(t/15)) %3D S¤(t) b) et y(t) ´z(t) c) y(t) et e3 d) { 2(t) l y(t) S¤(t) et et (c1 cos(t/15) + c2 sen(t/15)) || ||

Consider the differential equation zy" – v = (1) Making the changes of variable * = e', y = u(t)e 2* in the differential equation (1), we obtain the differential equation, u depending on t, u" – 6u' – bu = 0. The solution of the differential equation (1), depending on the parameter t, with constant c, and C2, is given by: a) { 2(t) y(t) ´z(t) et et (c1 cos(tv/15) + c2 sen(t/15)) %3D S¤(t) b) et y(t) ´z(t) c) y(t) et e3 d) { 2(t) l y(t) S¤(t) et et (c1 cos(t/15) + c2 sen(t/15)) || ||

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Consider the differential equation ry" - y =- 14y * = et, y = u(t)e 2t Making the changes of variable in the differential equation (1), we obtain the differential equation, u depending on t, u" – bu' – bu = 0. The solution of the differential equation (1), depending on the parameter t, with constant c, and C2, is given by: S¤(t) el a) y(t) et (c1 cos(t/15) + c2 sen(tv/15)) S2(t) b) et 3(t) = e (cieviB . ´z(t) c) y(t) et est S¤(t) = et d) y(t) e* (c1 cos(tv/15) + c2 sen(t/15))
Transcribed Image Text:Consider the differential equation ry" - y =- 14y * = et, y = u(t)e 2t Making the changes of variable in the differential equation (1), we obtain the differential equation, u depending on t, u" – bu' – bu = 0. The solution of the differential equation (1), depending on the parameter t, with constant c, and C2, is given by: S¤(t) el a) y(t) et (c1 cos(t/15) + c2 sen(tv/15)) S2(t) b) et 3(t) = e (cieviB . ´z(t) c) y(t) et est S¤(t) = et d) y(t) e* (c1 cos(tv/15) + c2 sen(t/15))
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