Consider the differential equation y" 2y' - 3y = 3te²t. - If the fundamental set of solutions to the complementary homogeneous solution is {e³t, et} and the particular solution is Yp -te²t 2 2t Že²², then the general solution to 3 the d.e. is: ○ y = e³t + e²+ - te²t - 2 3 2t 2t - 2 3 ezt y = C₁e³t + C₂et - te²t Оу = 2t = C₁e³t + C₂et - C3 (te² - 2 3t 2t 2 y = C₁e³ + C2e− − Cзte²² - C₁ e²² None of the above. =

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A: Differentiate both side with respect to x

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