Consider the differential equation [x² − (x³ + y³)²/³] dx + y² dy = 0. This is not an exact equation, but we may rearrange the equation as follows. 2 x² dx + y² dy (x³ + y³)2/3 = dx 1 Using the fact that d(x³ + y³) = x² dx + y² dy, / discuss how one could solve the differential equation.

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