Consider the differential equation -4y" + 5y" - 5y' − 3y = 0 with y(0) = -3, y'(0) = 3, y'(0) = 2. Taking the Laplace transform and solving for L(y) yields: L(y) = F(s) where F(s) = 12s²-27s+7 -45³+ 5s²-5s-3 Note: don't forget to substitute your initial conditions.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Consider the differential equation -4y"" + 5y" — 5y' − 3y = 0 with y(0) = −3, y′(0) = 3, y'(0) = 2. Taking the Laplace transform and solving for L(y) yields:
L(y) = F(s) where F(s) =
125²_
- 27s + 7
-48³ +5s²-5s-3
Note: don't forget to substitute your initial conditions.
Transcribed Image Text:Consider the differential equation -4y"" + 5y" — 5y' − 3y = 0 with y(0) = −3, y′(0) = 3, y'(0) = 2. Taking the Laplace transform and solving for L(y) yields: L(y) = F(s) where F(s) = 125²_ - 27s + 7 -48³ +5s²-5s-3 Note: don't forget to substitute your initial conditions.
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