Consider the decomposition of a metal oxide to its elements, where M represents a generic metal. Substance M3O4(s) M3O4(s) 3M(s) + 2O₂(g) M(s) O₂(g) What is the standard change in Gibbs energy for the reaction, as written, in the forward direction? -10.00 AGTxn = Incorrect What is the equilibrium constant of this reaction, as written, in the forward direction at 298 K? 56.57 K = Incorrect AG°f(kJ/mol) -10.00 0 0 kJ/mol

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What is the equilibrium pressure of O2(g) over M(s) at 298 K?
?O2= atm
### Decomposition of a Metal Oxide into its Elements

Consider the decomposition of a metal oxide to its elements, where \( \text{M} \) represents a generic metal. The reaction is given as:

\[ \text{M}_3\text{O}_4 (\text{s}) \rightleftharpoons 3 \text{M} (\text{s}) + 2 \text{O}_2 (\text{g}) \]

#### Standard Gibbs Energy Change

To determine the standard change in Gibbs energy for the reaction in the forward direction, we need to refer to the standard Gibbs free energy of formation (\( \Delta G_f^\circ \)) for each substance involved. The table provided includes these values:

| Substance   | \( \Delta G_f^\circ \) (kJ/mol) |
|-------------|-------------------------------|
| \( \text{M}_3\text{O}_4 (\text{s}) \) | -10.00                          |
| \( \text{M} (\text{s}) \)           | 0                               |
| \( \text{O}_2 (\text{g}) \)           | 0                               |

What is the standard change in Gibbs energy for the reaction, as written, in the forward direction?

\[
\Delta G_{\text{rxn}}^\circ = \boxed{-10.00} \, \text{kJ/mol}
\]

*Status: Incorrect*

#### Equilibrium Constant

Next, we determine the equilibrium constant (\( K \)) for this reaction at 298 K using the expression:

\[
\Delta G_{\text{rxn}}^\circ = -RT \ln K
\]

Given the value:

\[
K = \boxed{56.57}
\]

*Status: Incorrect*

### Explanation of Graphs/Diagrams

There are no additional graphs or diagrams included in this example. The information is presented in a textual format supplemented with a table of Gibbs free energy of formation values. The questions require calculating Gibbs free energy change and the equilibrium constant based on provided thermodynamic data.
Transcribed Image Text:### Decomposition of a Metal Oxide into its Elements Consider the decomposition of a metal oxide to its elements, where \( \text{M} \) represents a generic metal. The reaction is given as: \[ \text{M}_3\text{O}_4 (\text{s}) \rightleftharpoons 3 \text{M} (\text{s}) + 2 \text{O}_2 (\text{g}) \] #### Standard Gibbs Energy Change To determine the standard change in Gibbs energy for the reaction in the forward direction, we need to refer to the standard Gibbs free energy of formation (\( \Delta G_f^\circ \)) for each substance involved. The table provided includes these values: | Substance | \( \Delta G_f^\circ \) (kJ/mol) | |-------------|-------------------------------| | \( \text{M}_3\text{O}_4 (\text{s}) \) | -10.00 | | \( \text{M} (\text{s}) \) | 0 | | \( \text{O}_2 (\text{g}) \) | 0 | What is the standard change in Gibbs energy for the reaction, as written, in the forward direction? \[ \Delta G_{\text{rxn}}^\circ = \boxed{-10.00} \, \text{kJ/mol} \] *Status: Incorrect* #### Equilibrium Constant Next, we determine the equilibrium constant (\( K \)) for this reaction at 298 K using the expression: \[ \Delta G_{\text{rxn}}^\circ = -RT \ln K \] Given the value: \[ K = \boxed{56.57} \] *Status: Incorrect* ### Explanation of Graphs/Diagrams There are no additional graphs or diagrams included in this example. The information is presented in a textual format supplemented with a table of Gibbs free energy of formation values. The questions require calculating Gibbs free energy change and the equilibrium constant based on provided thermodynamic data.
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