Consider the DE y(x² + y) dx + x(x² – 2y) dy = 0. 3. The DE will become exact after multiplying it by an integrating factor e*, 4. The solution to the ODE is x²y – y² = c. 5. If y(1) = 2, the value of the arbitrary constant C is -2.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Consider the DE y(x² + y) dx + x(x² – 2y) dy = 0.
3. The DE will become exact after multiplying it by an integrating factor e*.
4. The solution to the ODE is x²y – y² = c.
5. If y(1) = 2, the value of the arbitrary constant C is -2.
%3D
Transcribed Image Text:Consider the DE y(x² + y) dx + x(x² – 2y) dy = 0. 3. The DE will become exact after multiplying it by an integrating factor e*. 4. The solution to the ODE is x²y – y² = c. 5. If y(1) = 2, the value of the arbitrary constant C is -2. %3D
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