Consider the data. x₁ 1 2 3 4 Y₁ 4 7 5 4 12 15 The estimated regression equation for these data is ŷ = 0.30 + 2.70x. (a) Compute SSE, SST, and SSR using equations SSE = (y₁ - y)², SST = (y₁ - y)², and SSR = (₁ - y)². SSE = SST = SSR = (b) Compute the coefficient of determination ². 2²= Comment on the goodness of fit. (For purposes of this exercise, consider a proportion large if it is at least 0.55.) O The least squares line did not provide a good fit as a small proportion of the variability in y has been explained by the least squares line. O The least squares line did not provide a good fit as a large proportion of the variability in y has been explained by the least squares line. The least squares line provided a good fit as a large proportion of the variability in y has been explained by the least squares line. O The least squares line provided a good fit as a small proportion of the variability in y has been explained by the least squares line. (c) Compute the sample correlation coefficient. (Round your answer to three decimal places.)
Consider the data. x₁ 1 2 3 4 Y₁ 4 7 5 4 12 15 The estimated regression equation for these data is ŷ = 0.30 + 2.70x. (a) Compute SSE, SST, and SSR using equations SSE = (y₁ - y)², SST = (y₁ - y)², and SSR = (₁ - y)². SSE = SST = SSR = (b) Compute the coefficient of determination ². 2²= Comment on the goodness of fit. (For purposes of this exercise, consider a proportion large if it is at least 0.55.) O The least squares line did not provide a good fit as a small proportion of the variability in y has been explained by the least squares line. O The least squares line did not provide a good fit as a large proportion of the variability in y has been explained by the least squares line. The least squares line provided a good fit as a large proportion of the variability in y has been explained by the least squares line. O The least squares line provided a good fit as a small proportion of the variability in y has been explained by the least squares line. (c) Compute the sample correlation coefficient. (Round your answer to three decimal places.)
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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![### Regression Analysis and Coefficient of Determination
Consider the data set below.
| \( x_i \) | 1 | 2 | 3 | 4 | 5 |
|-----------|---|---|---|---|---|
| \( y_i \) | 4 | 7 | 4 | 12 | 15 |
The estimated regression equation for these data is \( \hat{y} = 0.30 + 2.70x \).
#### (a) Compute SSE, SST, and SSR
Using the equations:
- SSE (Sum of Squared Errors): \( \Sigma (y_i - \hat{y})^2 \)
- SST (Total Sum of Squares): \( \Sigma (y_i - \bar{y})^2 \)
- SSR (Regression Sum of Squares): \( \Sigma (\hat{y} - \bar{y})^2 \)
- SSE = [Blank for student input]
- SST = [Blank for student input]
- SSR = [Blank for student input]
#### (b) Compute the coefficient of determination \( r^2 \)
The coefficient of determination is calculated as:
\[ r^2 = [Blank for student input] \]
**Comment on the goodness of fit.** (Consider a proportion large if it is at least 0.55.)
- \( \circ \) The least squares line did not provide a good fit as a small proportion of the variability in \( y \) has been explained by the least squares line.
- \( \circ \) The least squares line did not provide a good fit as a large proportion of the variability in \( y \) has been explained by the least squares line.
- \( \bullet \) The least squares line provided a good fit as a large proportion of the variability in \( y \) has been explained by the least squares line.
- \( \circ \) The least squares line provided a good fit as a small proportion of the variability in \( y \) has been explained by the least squares line.
#### (c) Compute the sample correlation coefficient.
Round your answer to three decimal places:
- [Blank for student input]
This exercise helps in understanding how to evaluate the quality of a regression model using various statistical measures and graphical interpretations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe2fdea76-24b5-4e92-ab93-0d275ab88ec3%2F3a5788c2-9b6f-4818-96db-1836c1f4d2fa%2Fw271bq_processed.png&w=3840&q=75)
Transcribed Image Text:### Regression Analysis and Coefficient of Determination
Consider the data set below.
| \( x_i \) | 1 | 2 | 3 | 4 | 5 |
|-----------|---|---|---|---|---|
| \( y_i \) | 4 | 7 | 4 | 12 | 15 |
The estimated regression equation for these data is \( \hat{y} = 0.30 + 2.70x \).
#### (a) Compute SSE, SST, and SSR
Using the equations:
- SSE (Sum of Squared Errors): \( \Sigma (y_i - \hat{y})^2 \)
- SST (Total Sum of Squares): \( \Sigma (y_i - \bar{y})^2 \)
- SSR (Regression Sum of Squares): \( \Sigma (\hat{y} - \bar{y})^2 \)
- SSE = [Blank for student input]
- SST = [Blank for student input]
- SSR = [Blank for student input]
#### (b) Compute the coefficient of determination \( r^2 \)
The coefficient of determination is calculated as:
\[ r^2 = [Blank for student input] \]
**Comment on the goodness of fit.** (Consider a proportion large if it is at least 0.55.)
- \( \circ \) The least squares line did not provide a good fit as a small proportion of the variability in \( y \) has been explained by the least squares line.
- \( \circ \) The least squares line did not provide a good fit as a large proportion of the variability in \( y \) has been explained by the least squares line.
- \( \bullet \) The least squares line provided a good fit as a large proportion of the variability in \( y \) has been explained by the least squares line.
- \( \circ \) The least squares line provided a good fit as a small proportion of the variability in \( y \) has been explained by the least squares line.
#### (c) Compute the sample correlation coefficient.
Round your answer to three decimal places:
- [Blank for student input]
This exercise helps in understanding how to evaluate the quality of a regression model using various statistical measures and graphical interpretations.
Expert Solution
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Step 1: Introduction
Correlation: The statistical relationship between two variables is known as correlation. The square of sample correlation coefficient known as Coefficient of determination.
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