The surface area of the surface of revolution resulting from revolving this curve about the y-axis is given by sec dy- c0.25T S = Soa C0.25" T tan Y V O The surface area of the surface of revolution resulting from revolving this curve about the x-axis is given by 0.25 sec S = So" 2n yV1+ dy- 4 The surface area of the surface of revolution resulting from revolving this curve about the y-axis is given by S = S" 27 x/1+ da. (1+2-²)? None are correct. The surface area of the surface of revolution resulting from revolving this curve about the y-axis is given by 0.5 S = 2T x1 + 4 dx. (1+42*)? %3D The surface area of the surface of revolution resulting from revolving this curve about the x-axis is given by S = S" 27 arctan(2x),/1+ 4 dx. 1+16z4 O The surface area of the surface of revolution resulting from revolving this curve about the a-axis is given by c0.5 = S" 27 arctan(2x),/1+ dx. (1+422)? Consider the curve y = arctan(2x) from x = 0 to x 0.5, shown in the graph. Choose all the correct %3D answers. 0.5+ y=arctan(2x) 0.5
The surface area of the surface of revolution resulting from revolving this curve about the y-axis is given by sec dy- c0.25T S = Soa C0.25" T tan Y V O The surface area of the surface of revolution resulting from revolving this curve about the x-axis is given by 0.25 sec S = So" 2n yV1+ dy- 4 The surface area of the surface of revolution resulting from revolving this curve about the y-axis is given by S = S" 27 x/1+ da. (1+2-²)? None are correct. The surface area of the surface of revolution resulting from revolving this curve about the y-axis is given by 0.5 S = 2T x1 + 4 dx. (1+42*)? %3D The surface area of the surface of revolution resulting from revolving this curve about the x-axis is given by S = S" 27 arctan(2x),/1+ 4 dx. 1+16z4 O The surface area of the surface of revolution resulting from revolving this curve about the a-axis is given by c0.5 = S" 27 arctan(2x),/1+ dx. (1+422)? Consider the curve y = arctan(2x) from x = 0 to x 0.5, shown in the graph. Choose all the correct %3D answers. 0.5+ y=arctan(2x) 0.5
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![The surface area of the surface of revolution resulting from revolving this curve about the y-axis is given by
sec
dy-
c0.25T
S = Soa
C0.25" T tan Y V
O The surface area of the surface of revolution resulting from revolving this curve about the x-axis is given by
0.25
sec
S = So" 2n yV1+
dy-
4
The surface area of the surface of revolution resulting from revolving this curve about the y-axis is given by
S = S" 27 x/1+
da.
(1+2-²)?
None are correct.
The surface area of the surface of revolution resulting from revolving this curve about the y-axis is given by
0.5
S = 2T x1 +
4
dx.
(1+42*)?
%3D
The surface area of the surface of revolution resulting from revolving this curve about the x-axis is given by
S = S" 27 arctan(2x),/1+
4
dx.
1+16z4
O The surface area of the surface of revolution resulting from revolving this curve about the a-axis is given by
c0.5
= S" 27 arctan(2x),/1+
dx.
(1+422)?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F54144759-0e64-4a52-9eb8-f3918d0f39d7%2F7f31fe3a-2bd7-4cba-b56a-ab50f8834389%2Fljc9jvx.jpeg&w=3840&q=75)
Transcribed Image Text:The surface area of the surface of revolution resulting from revolving this curve about the y-axis is given by
sec
dy-
c0.25T
S = Soa
C0.25" T tan Y V
O The surface area of the surface of revolution resulting from revolving this curve about the x-axis is given by
0.25
sec
S = So" 2n yV1+
dy-
4
The surface area of the surface of revolution resulting from revolving this curve about the y-axis is given by
S = S" 27 x/1+
da.
(1+2-²)?
None are correct.
The surface area of the surface of revolution resulting from revolving this curve about the y-axis is given by
0.5
S = 2T x1 +
4
dx.
(1+42*)?
%3D
The surface area of the surface of revolution resulting from revolving this curve about the x-axis is given by
S = S" 27 arctan(2x),/1+
4
dx.
1+16z4
O The surface area of the surface of revolution resulting from revolving this curve about the a-axis is given by
c0.5
= S" 27 arctan(2x),/1+
dx.
(1+422)?
![Consider the curve y = arctan(2x) from x = 0 to x
0.5, shown in the graph. Choose all the correct
%3D
answers.
0.5+
y=arctan(2x)
0.5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F54144759-0e64-4a52-9eb8-f3918d0f39d7%2F7f31fe3a-2bd7-4cba-b56a-ab50f8834389%2Fd6j0ovv.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the curve y = arctan(2x) from x = 0 to x
0.5, shown in the graph. Choose all the correct
%3D
answers.
0.5+
y=arctan(2x)
0.5
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