Consider the continuous random variable X whose pdf is given by f(2)=√15.50(2). (a) Find the value of k that makes f(x) a pdf. (b) Find E(X). (e) Find V(X). (d) Find P(X ≤ 4).

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A: (1) f′(x)=4x2+3x−3f(x)=∫f′(x)dxf(x)=∫(4x2+3x−3)dxUsing the Power Rule∫xndx=xn+1n+1+C

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A: f′(x)=5x,f(16)=49

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