### Understanding the Circuit#### Circuit DescriptionThis diagram represents a closed electrical circuit with the following components:- **Resistors:** - \( R_1 = 10 \, \text{k}\Omega \) - \( R_2 = 20 \, \text{k}\Omega \) - \( R_3 = 10 \, \text{k}\Omega \) - \( R_4 = 10 \, \text{k}\Omega \) - \( R_5 = 10 \, \text{k}\Omega \)- **Voltage Sources:** - \( V_1 = 12 \, \text{V} \) - \( V_2 = 24 \, \text{V} \)#### Circuit LayoutThe circuit is set up in a loop as follows:1. **Start at \( V_1 \):** - The positive terminal connects to \( R_1 \). 2. **Series Connections:** - \( R_1 \rightleftharpoons R_2 \) - \( R_2 \rightleftharpoons V_2 \) - \( V_2 \rightleftharpoons R_3 \) - \( R_3 \rightleftharpoons R_4 \) - \( R_4 \rightleftharpoons R_5 \) - \( R_5 \rightleftharpoons \) back to the negative terminal of \( V_1 \).#### ObjectiveCalculate the current that will flow in this circuit.To find the current, apply Ohm's Law and the rules for series circuits:1. **In series circuits**, the total resistance \( R_t \) is the sum of the individual resistances: \[ R_t = R_1 + R_2 + R_3 + R_4 + R_5 \]2. **Total Voltage** \( V_t \) is the sum of the voltages from \( V_1 \) and \( V_2 \): \[ V_t = V_1 + V_2 \]3. **Apply Ohm’s Law** to find the current \( I \): \[ I = \frac{V_t}{R_t} \]This analysis will help explain the electrical behavior of

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Answered: Consider the circut below R2 = 20 k2 -…

Consider the circut below R2 = 20 k2 - 10 k2 - 10 k2 EV, - 12 V V½ = 24 V R4 = 10 k2 Rs - 10 kf2 What is the current that will fow in this crouit?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Microscopic view of current

In physics, the term current is expressed as the rate of flow of electric charges across the area per unit time (I=q/t). It propagates along in the direction of the motion of positive charges. When the current is caused by the motion of electrons, the direction of the current is opposite to the flow.

Question

### Understanding the Circuit

#### Circuit Description

This diagram represents a closed electrical circuit with the following components:

- **Resistors:**
- \( R_1 = 10 \, \text{k}\Omega \)
- \( R_2 = 20 \, \text{k}\Omega \)
- \( R_3 = 10 \, \text{k}\Omega \)
- \( R_4 = 10 \, \text{k}\Omega \)
- \( R_5 = 10 \, \text{k}\Omega \)

- **Voltage Sources:**
- \( V_1 = 12 \, \text{V} \)
- \( V_2 = 24 \, \text{V} \)

#### Circuit Layout

The circuit is set up in a loop as follows:

1. **Start at \( V_1 \):**
- The positive terminal connects to \( R_1 \).

2. **Series Connections:**
- \( R_1 \rightleftharpoons R_2 \)
- \( R_2 \rightleftharpoons V_2 \)
- \( V_2 \rightleftharpoons R_3 \)
- \( R_3 \rightleftharpoons R_4 \)
- \( R_4 \rightleftharpoons R_5 \)
- \( R_5 \rightleftharpoons \) back to the negative terminal of \( V_1 \).

#### Objective

Calculate the current that will flow in this circuit.

To find the current, apply Ohm's Law and the rules for series circuits:

1. **In series circuits**, the total resistance \( R_t \) is the sum of the individual resistances:

\[
R_t = R_1 + R_2 + R_3 + R_4 + R_5
\]

2. **Total Voltage** \( V_t \) is the sum of the voltages from \( V_1 \) and \( V_2 \):

\[
V_t = V_1 + V_2
\]

3. **Apply Ohm’s Law** to find the current \( I \):

\[
I = \frac{V_t}{R_t}
\]

This analysis will help explain the electrical behavior of

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