Consider the circuit shown in the figure, with C, - 5.42 µF and C, - 7.14 pF. 6.00 uF HP 2.00 uF 90.0 V (a) Find the equivalent capacitance (in uF) of the system. HF (b) Find the charge (in µC) on each capacitor. . 5.42 pF capacitor 4.185 Note that the same potential difference, equal to the potential difference of the battery, exists across both the upper and lower branches. Recall that each of the capacitors in series combination holds the same charge as that on the equivalent capacitor, and that Q - CAV. Use this information to help you determine the charge on each capacitor. µC 37.7 6.00 uF capacitor Note that the same potential difference, equal to the potential difference of the battery, exists across both the upper and lower branches. Recall that each of the capacitors in series combination holds the same charge as that on the equivalent capacitor, and that Q - CAV. Use this information to help you determine the charge on each capacitor. µC 23.5 7.14 pF capacitor Note that the same potential difference, equal to the potential difference of the battery, exists across both the upper and lower branches. Recall that each of the capacitors in series combination holds the same charge as that on the equivalent capacitor, and that Q = CAV. Use this information to help you determine the charge on each capacitor. µC 2.00 pF 14.2 сараcitor Note that the same potential difference, equal to the potential difference of the battery, exists across both the upper and lower branches. Recall that each of the capacitors in series combination holds the same charge as that on the equivalent capacitor, and that Q = CAV. Use this information to help you determine the charge on each capacitor. µC (c) Find the potential difference (in V) on each capacitor. 5.42 pF capacitor 1.18 The potential difference across each of the capacitors in the circuit is given by AV = . Use this relationship and the charge found in part (b) to find the desired values. V 6.00 µF capacitor 1.18 The potential difference across each of the capacitors in the circuit is given by AV = 2. Use this relationship and the charge found in part (b) to find the desired values. V 7.14 pF capacitor V 2.00 uF capacitor V