**Circuit Analysis and Time Constants**Consider the circuit shown in the figure below. Let the electromotive force \( \varepsilon = 10.00 \, \text{V} \), the inductance \( L = 12 \, \text{mH} \), and the resistance \( R = 9 \, \Omega \). The circuit diagram includes a battery, a switch \( S \), a resistor \( R \), and an inductor \( L \) in series.**Key Questions:**(a) What is the inductive time constant of the circuit?(b) Calculate the current in the circuit 100 μs after the switch is closed.(c) What is the value of the final steady-state current?(d) How long does it take the current to reach 75.0% of its maximum value?**Explanation of the Diagram:**- **Battery (\( \varepsilon \)):** Provides a constant voltage of 10.00 V.- **Switch \( S \):** Controls the flow of current; in this scenario, it is considered to be closed.- **Resistor \( R \):** With a resistance of 9 Ω, it limits the current flow in the circuit.- **Inductor \( L \):** With an inductance of 12 mH, it opposes changes in current flow.This configuration represents a classic series RL circuit, which is essential for analyzing transient response and time constants.

Given information: E = 10 V L = 12 mHR = 9Ω

Answered: Consider the circuit shown in the…

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