Consider the circuit shown in Figure. 5.0 Ω 3.0 N 3.0 N 10n3 -4.0 Ω 28 V 10 Ω. 4.0 N 2.0 N 3.0 Ω 1. The equivalent resistance of the above circuit is = 2. The total current supplied by the battery is = A 3. The potential differences across 52 = V 4. The Power dissipated in the circuit is = W

Consider the circuit shown in Figure. 5.0 Ω 3.0 N 3.0 N 10n3 -4.0 Ω 28 V 10 Ω. 4.0 N 2.0 N 3.0 Ω 1. The equivalent resistance of the above circuit is = 2. The total current supplied by the battery is = A 3. The potential differences across 52 = V 4. The Power dissipated in the circuit is = W

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Ohm's law

Ohm’s law is a prominent concept in physics and electronics. It gives the relation between the current and the voltage. It is used to analyze and construct electrical circuits. Ohm's law states that the voltage across a conductor is directly proportional to the current flowing through it.

Path of Least Resistance

In a series of alternate pathways, the direction of least resistance is the actual or metaphorical route that offers the least resistance to forwarding motion by a given individual or body.

Question

Consider the circuit shown in Figure.
5.0 Ω
3.0 N
3.0 N
10n3
-4.0 Ω
28 V
10 Ω.
4.0 N
2.0 N
3.0 Ω
1. The equivalent resistance of the above circuit is =
2. The total current supplied by the battery is =
A
3. The potential differences across 52 =
V
4. The Power dissipated in the circuit is =
W

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