Consider the circuit shown in Figure.2.00 N3.00Q1.00 N18.0 V4.00 N1. The equivalent resistance of the above circuit is =2. The total current supplied by the battery is =A3. The potential differences across 30, 10 is=4. The Power dissipated in the 20 is =W & Power dissipated 42 is =W5. The power dissipated across 10 is =W & Power dissipated 30 is =W

let R1 = 2 ohm R2 = 3 ohm R3 = 1 ohm R4 = 4 ohm V =18.0 V

Consider the circuit shown in Figure. 2.00 N 3.00 Q 1.00 N 18.0 V 4.00 N 1. The equivalent resistance of the above circuit is = 2. The total current supplied by the battery is = 3. The potential differences across 30, 10 is= 4. The Power dissipated in the 20 is = W & Power dissipated 40 is W 5. The power dissipated across 10 is = W & Power dissipated 30 is = W

Consider the circuit shown in Figure. 2.00 N 3.00 Q 1.00 N 18.0 V 4.00 N 1. The equivalent resistance of the above circuit is = 2. The total current supplied by the battery is = 3. The potential differences across 30, 10 is= 4. The Power dissipated in the 20 is = W & Power dissipated 40 is W 5. The power dissipated across 10 is = W & Power dissipated 30 is = W

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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