Consider the circuit shown below left. ww 100 Ω 5 V SW1 500 mH ww 100 02 ww Rth Vth SW1 a ell 500 mH a. The switch and inductor can viewed as being attached to Thevenin equivalent circuit shown (above right). Show that Vth=2.5V and Rth=50 2. b. Derive the governing equation for the inductor current using KVL and state the initial condition. c. Solve the governing equation to determine the current through the inductor with time if the switch is closed at t=0. d. What is the time constant t for the circuit? What is the current at t=t? e. Plot the current across the inductor vs. time. f. Plot the voltage across the inductor vs. time.

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Please answer, d-f plz
## Circuit Analysis Exercise

### Circuit Diagram

- **Left Circuit:** 
  - A 5 V battery is connected in series with a switch (SW1), a 100 Ω resistor, and a 500 mH inductor.
  
- **Right Circuit (Thevenin Equivalent):** 
  - The circuit components are replaced by an ideal voltage source (Vth) in series with a resistor (Rth) and a 500 mH inductor. 

### Tasks

#### a. Thevenin Equivalent
- Demonstrate that the Thevenin equivalent voltage (Vth) is 2.5 V and the Thevenin equivalent resistance (Rth) is 50 Ω.

#### b. Govern Equation
- Derive the equation governing the inductor current using Kirchhoff’s Voltage Law (KVL) and specify the initial condition.

#### c. Solution for Inductor Current
- Solve the governing equation to find the inductor current over time, given that the switch is closed at t=0.

#### d. Time Constant and Current
- Calculate the time constant (τ) for the circuit.
- Determine the current at t=τ.

#### e. Current vs. Time Plot
- Create a plot illustrating the current across the inductor over time.

#### f. Voltage vs. Time Plot
- Create a plot showing the voltage across the inductor over time.

### Additional Notes
- The analysis uses fundamental principles of electrical engineering, emphasizing the application of Thevenin’s Theorem and KVL.
- The time constant is a critical parameter indicating how quickly the current reaches a steady state.
- The plots required in tasks e and f provide a visual representation of how current and voltage evolve, offering deeper insight into inductor behavior in circuits.
Transcribed Image Text:## Circuit Analysis Exercise ### Circuit Diagram - **Left Circuit:** - A 5 V battery is connected in series with a switch (SW1), a 100 Ω resistor, and a 500 mH inductor. - **Right Circuit (Thevenin Equivalent):** - The circuit components are replaced by an ideal voltage source (Vth) in series with a resistor (Rth) and a 500 mH inductor. ### Tasks #### a. Thevenin Equivalent - Demonstrate that the Thevenin equivalent voltage (Vth) is 2.5 V and the Thevenin equivalent resistance (Rth) is 50 Ω. #### b. Govern Equation - Derive the equation governing the inductor current using Kirchhoff’s Voltage Law (KVL) and specify the initial condition. #### c. Solution for Inductor Current - Solve the governing equation to find the inductor current over time, given that the switch is closed at t=0. #### d. Time Constant and Current - Calculate the time constant (τ) for the circuit. - Determine the current at t=τ. #### e. Current vs. Time Plot - Create a plot illustrating the current across the inductor over time. #### f. Voltage vs. Time Plot - Create a plot showing the voltage across the inductor over time. ### Additional Notes - The analysis uses fundamental principles of electrical engineering, emphasizing the application of Thevenin’s Theorem and KVL. - The time constant is a critical parameter indicating how quickly the current reaches a steady state. - The plots required in tasks e and f provide a visual representation of how current and voltage evolve, offering deeper insight into inductor behavior in circuits.
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