Consider the circuit below. The battery has an open-circuit voltage of ɛ = 30 V and an internal resistance of r = 12. = 18.00 N E = 30.00 V R1 = 9.00 N : = 1.00 2 R3 = 10.00 N: R5 = 8.00 N R4 = 10.00 2 Hint a. Find the equivalent resistance of the circuit (not including the internal resistance). Reg = b. Find the current out of the battery (do not ignore the internal resistance). Ibat = А c. Find the potential drop across each resistor. Across R1 and R2: AV = V. Across R3 and R4: AV = V. Across R5: AV = V. Across r: AV = V. (These drops should add up to the value of ɛ.) d. Find the currents through Rị and R2: IRI = А IR2 = e. Find the currents through R3 and R4: IR3 = А IRA A f. What is the percentage of the total power supplied by the battery that is dissipated in the internal resistance of the battery? A total of % of the total power supplied by the battery is dissipated in the internal resistance r.
Consider the circuit below. The battery has an open-circuit voltage of ɛ = 30 V and an internal resistance of r = 12. = 18.00 N E = 30.00 V R1 = 9.00 N : = 1.00 2 R3 = 10.00 N: R5 = 8.00 N R4 = 10.00 2 Hint a. Find the equivalent resistance of the circuit (not including the internal resistance). Reg = b. Find the current out of the battery (do not ignore the internal resistance). Ibat = А c. Find the potential drop across each resistor. Across R1 and R2: AV = V. Across R3 and R4: AV = V. Across R5: AV = V. Across r: AV = V. (These drops should add up to the value of ɛ.) d. Find the currents through Rị and R2: IRI = А IR2 = e. Find the currents through R3 and R4: IR3 = А IRA A f. What is the percentage of the total power supplied by the battery that is dissipated in the internal resistance of the battery? A total of % of the total power supplied by the battery is dissipated in the internal resistance r.
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**Electric Circuit Analysis**
Consider the circuit below. The battery has an open-circuit voltage of \( \mathcal{E} = 30 \, \text{V} \) and an internal resistance of \( r = 1 \, \Omega \).
**Circuit Diagram:**
- The circuit includes a battery with an open-circuit voltage of 30 V and an internal resistance of 1 Ω.
- The resistors are arranged as follows:
- \( R_1 = 9.00 \, \Omega \)
- \( R_2 = 18.00 \, \Omega \)
- \( R_3 = 10.00 \, \Omega \)
- \( R_4 = 10.00 \, \Omega \)
- \( R_5 = 8.00 \, \Omega \)
**Tasks:**
a. **Find the equivalent resistance** of the circuit (not including the internal resistance).
\[
R_{\text{eq}} = \boxed{\,\,} \, \Omega
\]
b. **Find the current out of the battery** (do not ignore the internal resistance).
\[
I_{\text{bat}} = \boxed{\,\,} \, \text{A}
\]
c. **Find the potential drop across each resistor.**
- Across \( R_1 \) and \( R_2 \): \( \Delta V = \boxed{\,\,} \, \text{V} \)
- Across \( R_3 \) and \( R_4 \): \( \Delta V = \boxed{\,\,} \, \text{V} \)
- Across \( R_5 \): \( \Delta V = \boxed{\,\,} \, \text{V} \)
- Across \( r \): \( \Delta V = \boxed{\,\,} \, \text{V} \)
- (These drops should add up to the value of \( \mathcal{E} \).)
d. **Find the currents through \( R_1 \) and \( R_2 \):**
\[
I_{R_1} = \boxed{\,\,} \, \text{A}
\]
\[
I_{R_2} = \boxed{\,\,}](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe09d4462-f34d-4530-ac40-5ce52271c7b7%2F8fa86c96-0b3d-4030-9dba-1d0e821e52f8%2Fnykadac_processed.png&w=3840&q=75)
Transcribed Image Text:---
**Electric Circuit Analysis**
Consider the circuit below. The battery has an open-circuit voltage of \( \mathcal{E} = 30 \, \text{V} \) and an internal resistance of \( r = 1 \, \Omega \).
**Circuit Diagram:**
- The circuit includes a battery with an open-circuit voltage of 30 V and an internal resistance of 1 Ω.
- The resistors are arranged as follows:
- \( R_1 = 9.00 \, \Omega \)
- \( R_2 = 18.00 \, \Omega \)
- \( R_3 = 10.00 \, \Omega \)
- \( R_4 = 10.00 \, \Omega \)
- \( R_5 = 8.00 \, \Omega \)
**Tasks:**
a. **Find the equivalent resistance** of the circuit (not including the internal resistance).
\[
R_{\text{eq}} = \boxed{\,\,} \, \Omega
\]
b. **Find the current out of the battery** (do not ignore the internal resistance).
\[
I_{\text{bat}} = \boxed{\,\,} \, \text{A}
\]
c. **Find the potential drop across each resistor.**
- Across \( R_1 \) and \( R_2 \): \( \Delta V = \boxed{\,\,} \, \text{V} \)
- Across \( R_3 \) and \( R_4 \): \( \Delta V = \boxed{\,\,} \, \text{V} \)
- Across \( R_5 \): \( \Delta V = \boxed{\,\,} \, \text{V} \)
- Across \( r \): \( \Delta V = \boxed{\,\,} \, \text{V} \)
- (These drops should add up to the value of \( \mathcal{E} \).)
d. **Find the currents through \( R_1 \) and \( R_2 \):**
\[
I_{R_1} = \boxed{\,\,} \, \text{A}
\]
\[
I_{R_2} = \boxed{\,\,}
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