Consider the circuit below, with R = 802, C₁ = 0.04F, L₁= 2H and L₂=3H, calculate the node voltages V₁ and V₂. Select the correct answer below with the angles in degrees. V₁ C₁ + L₁ 000000 Va R www 40 cos (5t -20°) V O V₁(t) = 39.92 cos(5t -22.81°) V; V₂(t) = 39.57 cos(5t -19.91°) V O V₁(t) = 40.15 cos(5t -22.59 °) V; V₂(t) = 39.99 cos(5t -16.88°) V O V₁(t) = 40.33 cos(5t-22.35 °) V; V₂(t) = 40.45 cos(5t-13.85°) V O V₁(t) = 40.74 cos(5t-18.09 °) V; V₂(t) = 44.65 cos(5t +2.47°) V O V₁(t) = 40.83 cos(5t-17.48 °) V; V₂(t) = 46.25 cos(5t +8.1 °) V O V₁(t) = 40.95 cos(5t -16.93°) V; V₂(t) = 48.29 cos(5t +13.1 °) V O V₁(t) = 42.11 cos(5t-10.44 °) V; V₂(t) = 75.45 cos(5t +36.60 °) V O V1(t) = 41.664 cos(5t -8.94°) V; V₂(t) = 80.47 cos(5t +44.61 °) V O V₁(t) = 41.53 cos(5t -7.74°) V; V₂(t) = 86.87 cos(5t +49.8 °) V V₁(t)=40.44 cos(5t-17.43°) V: V₂(t) = 45.91 cos(5t +8 36°) Y 45 www. L2 V₂ 3V₂

Consider the circuit below, with R = 802, C₁ = 0.04F, L₁= 2H and L₂=3H, calculate the node voltages V₁ and V₂. Select the correct answer below with the angles in degrees. V₁ C₁ + L₁ 000000 Va R www 40 cos (5t -20°) V O V₁(t) = 39.92 cos(5t -22.81°) V; V₂(t) = 39.57 cos(5t -19.91°) V O V₁(t) = 40.15 cos(5t -22.59 °) V; V₂(t) = 39.99 cos(5t -16.88°) V O V₁(t) = 40.33 cos(5t-22.35 °) V; V₂(t) = 40.45 cos(5t-13.85°) V O V₁(t) = 40.74 cos(5t-18.09 °) V; V₂(t) = 44.65 cos(5t +2.47°) V O V₁(t) = 40.83 cos(5t-17.48 °) V; V₂(t) = 46.25 cos(5t +8.1 °) V O V₁(t) = 40.95 cos(5t -16.93°) V; V₂(t) = 48.29 cos(5t +13.1 °) V O V₁(t) = 42.11 cos(5t-10.44 °) V; V₂(t) = 75.45 cos(5t +36.60 °) V O V1(t) = 41.664 cos(5t -8.94°) V; V₂(t) = 80.47 cos(5t +44.61 °) V O V₁(t) = 41.53 cos(5t -7.74°) V; V₂(t) = 86.87 cos(5t +49.8 °) V V₁(t)=40.44 cos(5t-17.43°) V: V₂(t) = 45.91 cos(5t +8 36°) Y 45 www. L2 V₂ 3V₂

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

A resistor, a capacitor, and an inductor are connected in series with a mystery component. The resistor has a resistance of 500Ω, the capacitor has a reactance of 100Ω, and the inductor has a reactance of 500Ω. The total impedance of the circuit is 700+j400Ω . What is the mystery component?
help me!!!
please do the mesh analysis one
Determine v(t), the voltage across the 40 ohm resistor in the circuit in Figure P 5.3-7
by Thevenin's theorem find the Vth and Rth to 150 ohm
Compute the complex power supplied by the current source in the series RLC circuit in look to the figure w m- L,cos at O Jlġull MEDIA
Looking at the circuit in Figure 1, the current source Is and the voltage source Vs are 8220° A and 3.5Vx V respectively. Using source transformation, (a) Reduce the circuit to one source and then obtain the values of Is and Vx. (b) Determine if Ix is leading or lagging Is, and their angle difference if any. j4 N I + Vx - ll 7Ω 2Ω j2 2 Is -j5 N J3Ω Vs Figure 1 ele ell
1. For the circuit shown below, use the current divider rule to find the phasors 13 and Vo in polar form: answer: 13 = 7.694 65.3° A, V₁ =¹46.161 Z-24.7° V 1₁ = 940° A ↑ R₁ 15 02 L₁ j8n A₂ www. 4Ω 13↓ с -j6n Hii + V₂ R3 ΖΩ L₂ j5Ω
R,r ,L and C are connected in series and the voltages across them are measured as below. VR VC VRlrc VLrC 0.144 V 0.48 V 0.486 V 0.147 V 0.261 V Draw a phasor diagram and use it to find V and V
Find the voltages in their rectangular form (Solve by node method) -j5 N 1/0° A ( 2 + j4 N 4 - j2 N *) 0.5/-90° A Ref. (b)
The Total Voltage in an RC Series Circuit splits or gets distributed across the Resistance and Capacitive Reactance. Select one: True False
25