Consider the charged capacitor below, that is not connected to anything. The capacitor originally has vacuum between its plates. As a dielectric is inserted between the plates, what will happen to the amount of charge on the positive capacitor plate? C1 O It will increase. O It will decrease. O It will stay the same.
Consider the charged capacitor below, that is not connected to anything. The capacitor originally has vacuum between its plates. As a dielectric is inserted between the plates, what will happen to the amount of charge on the positive capacitor plate? C1 O It will increase. O It will decrease. O It will stay the same.
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
Transcribed Image Text:Consider the charged capacitor below, that is not connected to anything. The capacitor
originally has vacuum between its plates. As a dielectric is inserted between the plates,
what will happen to the amount of charge on the positive capacitor plate?
C1
O It will increase.
It will decrease.
O It will stay the same.
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