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Consider the case of a continous variable of interest, call it X. Its density function is given by 1 8192 f(x) = 1 128 e (x - 50)² TC √√2 What is the proportion of the population with an X value smaller than the 32-th percentile or greater than the 44-th percentile of this distribution? (Hint: Don't be impressed by f(x) or think that you have to employ some fancy calculus technique to find the answer. The answer can be found quickly. Just take a moment and think carefully.)

Consider the case of a continous variable of interest, call it X. Its density function is given by 1 8192 f(x) = 1 128 e (x - 50)² TC √√2 What is the proportion of the population with an X value smaller than the 32-th percentile or greater than the 44-th percentile of this distribution? (Hint: Don't be impressed by f(x) or think that you have to employ some fancy calculus technique to find the answer. The answer can be found quickly. Just take a moment and think carefully.)

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Consider the case of a continous variable of interest, call it X. Its density function is given by 1 8192 f(x) = 1 128 e (x - 50)² TU √√2 What is the proportion of the population with an X value smaller than the 32-th percentile or greater than the 44-th percentile of this distribution? (Hint: Don't be impressed by f(x) or think that you have to employ some fancy calculus technique to find the answer. The answer can be found quickly. Just take a moment and think carefully.)
Transcribed Image Text:Consider the case of a continous variable of interest, call it X. Its density function is given by 1 8192 f(x) = 1 128 e (x - 50)² TU √√2 What is the proportion of the population with an X value smaller than the 32-th percentile or greater than the 44-th percentile of this distribution? (Hint: Don't be impressed by f(x) or think that you have to employ some fancy calculus technique to find the answer. The answer can be found quickly. Just take a moment and think carefully.)
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