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Consider the Bubble Sort algorithm we developed in class. It works, but it may waste some activity. Starting with the code from class, make the following modifications, to make Bubble Sort more efficient. 1. After the first pass, the largest number is guaranteed to be in the highest numbered array index; after the second pass, the two highest numbers are in place; and so on. Modify the code so the sorting algorithm doesn't bother to make comparisons with these already-in- place elements. For an array of size n, in the first pass n-1 comparisons are required; on the second pass n-2 comparisons are required, etc. 2. What if the array is already sorted? We may be doing all these comparisons, and never changing anything in the array. Modify the sorting algorithm to check at the end of each pass whether any swaps have been made. If no swaps have been made, the array must already be sorted, so you should end the sort. If at least one swap has been made, then at least one more pass through the array is required.

Consider the Bubble Sort algorithm we developed in class. It works, but it may waste some activity. Starting with the code from class, make the following modifications, to make Bubble Sort more efficient. 1. After the first pass, the largest number is guaranteed to be in the highest numbered array index; after the second pass, the two highest numbers are in place; and so on. Modify the code so the sorting algorithm doesn't bother to make comparisons with these already-in- place elements. For an array of size n, in the first pass n-1 comparisons are required; on the second pass n-2 comparisons are required, etc. 2. What if the array is already sorted? We may be doing all these comparisons, and never changing anything in the array. Modify the sorting algorithm to check at the end of each pass whether any swaps have been made. If no swaps have been made, the array must already be sorted, so you should end the sort. If at least one swap has been made, then at least one more pass through the array is required.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Consider the Bubble Sort algorithm we developed in class. It works, but it may waste some activity. Starting with the code from class, make the following modifications, to make Bubble Sort more efficient. 1. After the first pass, the largest number is guaranteed to be in the highest numbered array index; after the second pass, the two highest numbers are in place; and so on. Modify the code so the sorting algorithm doesn't bother to make comparisons with these already-in- place elements. For an array of size n, in the first pass n-1 comparisons are required; on the second pass n-2 comparisons are required, etc. 2. What if the array is already sorted? We may be doing all these comparisons, and never changing anything in the array. Modify the sorting algorithm to check at the end of each pass whether any swaps have been made. If no swaps have been made, the array must already be sorted, so you should end the sort. If at least one swap has been made, then at least one more pass through the array is required.
Transcribed Image Text:Consider the Bubble Sort algorithm we developed in class. It works, but it may waste some activity. Starting with the code from class, make the following modifications, to make Bubble Sort more efficient. 1. After the first pass, the largest number is guaranteed to be in the highest numbered array index; after the second pass, the two highest numbers are in place; and so on. Modify the code so the sorting algorithm doesn't bother to make comparisons with these already-in- place elements. For an array of size n, in the first pass n-1 comparisons are required; on the second pass n-2 comparisons are required, etc. 2. What if the array is already sorted? We may be doing all these comparisons, and never changing anything in the array. Modify the sorting algorithm to check at the end of each pass whether any swaps have been made. If no swaps have been made, the array must already be sorted, so you should end the sort. If at least one swap has been made, then at least one more pass through the array is required.
#include <stdio.h> #define SIZE 10 // function main begins program execution int main(void){ // initialize a int a[sIzE] {2, 6, 4, 8, 10, 12, 89, 68, 45, 37}; puts ("Data items in original order"); // output original array for (size_t i = 0; i < SIZE; ++i) { printf( "%4d", a[i]); } / bubble sort / loop to control number of passes for (unsigned int pass = 1; pass < SIZE; ++pass) { / loop to control number of comparisons per pass for (size_t i = 0; i < SIZE 1; ++i) { - / compare adjacent elements and swap them if first / element is greater than second element if (ali] > a[i + 1]) { int hold = a[i]; ali + 1]; ali+ 1] = hold; a[i] = } } puts ("\nData items in ascending order"); // output sorted array for (size_t i = ®; i < SIZE; ++i) { printf( "%4d", a[i]); puts (""); }
Transcribed Image Text:#include <stdio.h> #define SIZE 10 // function main begins program execution int main(void){ // initialize a int a[sIzE] {2, 6, 4, 8, 10, 12, 89, 68, 45, 37}; puts ("Data items in original order"); // output original array for (size_t i = 0; i < SIZE; ++i) { printf( "%4d", a[i]); } / bubble sort / loop to control number of passes for (unsigned int pass = 1; pass < SIZE; ++pass) { / loop to control number of comparisons per pass for (size_t i = 0; i < SIZE 1; ++i) { - / compare adjacent elements and swap them if first / element is greater than second element if (ali] > a[i + 1]) { int hold = a[i]; ali + 1]; ali+ 1] = hold; a[i] = } } puts ("\nData items in ascending order"); // output sorted array for (size_t i = ®; i < SIZE; ++i) { printf( "%4d", a[i]); puts (""); }
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