Consider the boundary value problem: x²y''(x) + xy'(x) − (x² + 2.89) y(x) = 0 where y(0) = 0 and y(7.88) = 3.61 Use the collocation method to approximate the the value of the solution when x = 3.27. In other words, to approximate the value of y(3.27). Use a 4th degree polynomial as the trial function and use the collocation points x = 1.32, x = 2.47, and x = 3.41. Your answer must be accurate to 4 decimal digits (i.e., your answer correct answer| ≤ 0.00005). Note: this is different to rounding to 4 decimal places You should maintain at least eight decimal digits of precision throughout all calculations. y(3.27) Skipped

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Consider the boundary value problem:
x²y''(x) + xy'(x) − (x² + 2.89) y(x) = 0 where y(0) = 0 and y(7.88) = 3.61
Use the collocation method to approximate the the value of the solution when x = 3.27. In other words, to approximate the value of y(3.27).
Use a 4th degree polynomial as the trial function and use the collocation points x = 1.32, x = 2.47, and x = 3.41.
Your answer must be accurate to 4 decimal digits (i.e., your answer correct answer| ≤ 0.00005).
Note: this is different to rounding to 4 decimal places
You should maintain at least eight decimal digits of precision throughout all calculations.
y(3.27) Skipped
Transcribed Image Text:Consider the boundary value problem: x²y''(x) + xy'(x) − (x² + 2.89) y(x) = 0 where y(0) = 0 and y(7.88) = 3.61 Use the collocation method to approximate the the value of the solution when x = 3.27. In other words, to approximate the value of y(3.27). Use a 4th degree polynomial as the trial function and use the collocation points x = 1.32, x = 2.47, and x = 3.41. Your answer must be accurate to 4 decimal digits (i.e., your answer correct answer| ≤ 0.00005). Note: this is different to rounding to 4 decimal places You should maintain at least eight decimal digits of precision throughout all calculations. y(3.27) Skipped
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