Consider the AVL Tree below. Use the AVL Tree Insertion algorithm to add 99 to the tree. List the nodes of the resulting tree in pre-order traversal order separated by one blank character. For example, the tree below can be described in the above format as: 66 22 30 77 70 92 85 98 2 0022 0030 0066 0077 0070 3 0092 2 0085 0098 1

Consider the AVL Tree below. Use the AVL Tree Insertion algorithm to add 99 to the tree. List the nodes of the resulting tree in pre-order traversal order separated by one blank character. For example, the tree below can be described in the above format as: 66 22 30 77 70 92 85 98 2 0022 0030 0066 0077 0070 3 0092 2 0085 0098 1

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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def solve_n_queens(n): def is_safe(board, row, col): # Verificar la columna for i in range(row): if board[i][col] == 1: return False # Verificar la diagonal izquierda i, j = row, col while i >= 0 and j >= 0: if board[i][j] == 1: return False i -= 1 j -= 1 # Verificar la diagonal derecha i, j = row, col while i >= 0 and j < n: if board[i][j] == 1: return False i -= 1 j += 1 return True def solve(board, row): if row >= n: solution = [] for r in board: solution.append("".join(['R' if x == 1 else '.' for x in r])) solutions.append(solution) return for col in range(n): if is_safe(board, row, col): board[row][col] = 1 solve(board, row + 1)…
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def solve_n_queens(n): def is_safe(board, row, col): # Verificar la columna for i in range(row): if board[i][col] == 1: return False # Verificar la diagonal izquierda i, j = row, col while i >= 0 and j >= 0: if board[i][j] == 1: return False i -= 1 j -= 1 # Verificar la diagonal derecha i, j = row, col while i >= 0 and j < n: if board[i][j] == 1: return False i -= 1 j += 1 return True def solve(board, row): if row >= n: solution = [] for r in board: solution.append("".join(['Q' if x == 1 else '.' for x in r])) solutions.append(solution) return for col in range(n): if is_safe(board, row, col): board[row][col] = 1 solve(board, row + 1)…
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