Consider the Atwood machine shown in the figure, where  m1 = 2.00 kg  and  m2 = 6.85 kg.  The system starts at rest, then the sphere is given a quick push downward, giving it an initial speed of 2.15 m/s.   Assume the pulley and cord are massless, and the cord is inextensible. Neglect friction. (a) Through what distance (in m) will m1 descend? (b) What is the velocity (in m/s) of m1 after 1.80 s?

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Chapter1: Units, Trigonometry. And Vectors
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Consider the Atwood machine shown in the figure, where 

m1 = 2.00 kg

 and 

m2 = 6.85 kg.

 The system starts at rest, then the sphere is given a quick push downward, giving it an initial speed of 2.15 m/s.

 

Assume the pulley and cord are massless, and the cord is inextensible. Neglect friction.
(a)
Through what distance (in m) will m1 descend?
(b)
What is the velocity (in m/s) of m1 after 1.80 s?
Consider the Atwood machine shown in the figure, where m, = 2.00 kg and m, = 6.85 kg. The system starts at rest, then
the sphere is given a quick push downward, giving it an initial speed of 2.15 m/s.
m2
Assume the pulley and cord are massless, and the cord is inextensible. Neglect friction.
(a) Through what distance (in m) will m, descend?
0.861
Write Newton's second law for each mass, and solve the system of equations for a. Then use your result in a
kinematics equation to determine the distance. m
(b) What is the velocity (in m/s) of m, after 1.80 s?
|-7.52
Apply a kinematics equation and the acceleration used to solve part (a) to find the magnitude of the
velocity at the given time. m/s
magnitude
direction
upward
Transcribed Image Text:Consider the Atwood machine shown in the figure, where m, = 2.00 kg and m, = 6.85 kg. The system starts at rest, then the sphere is given a quick push downward, giving it an initial speed of 2.15 m/s. m2 Assume the pulley and cord are massless, and the cord is inextensible. Neglect friction. (a) Through what distance (in m) will m, descend? 0.861 Write Newton's second law for each mass, and solve the system of equations for a. Then use your result in a kinematics equation to determine the distance. m (b) What is the velocity (in m/s) of m, after 1.80 s? |-7.52 Apply a kinematics equation and the acceleration used to solve part (a) to find the magnitude of the velocity at the given time. m/s magnitude direction upward
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