Consider the area shown in (Figure 1). Suppose that a=h=b=130 mm. Figure 1 of 1 h y=x Xy=11² Part A Locate the centroid y of the area. Express your answer to three significant figures and include the appropria → ? y = Value Units Submit Provide Feedback Request Answer

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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### Problem Statement:

Consider the area shown in (Figure 1). Suppose that:

\( a = h = b = 130 \) mm

**Part A:**
Locate the centroid \( \bar{y} \) of the area.

Express your answer to three significant figures and include the appropriate units.

#### Answer Box:
\[ \bar{y} = \text{Value} \, \text{Units} \]

Click Submit to provide your answer.


### Figure Explanation:

#### Figure 1:
The graph consists of two functions plotted on the Cartesian plane:

1. **Function 1**: \( y = x \)
2. **Function 2**: \( y = \frac{a}{h} x^2 \)

The enclosed area between these two curves lies between \( x = 0 \) and \( x = b \), forming a shaded region. The coordinate axes are labeled as \( x \) (horizontal axis) and \( y \) (vertical axis). The intersection of the curves with the axes are at:

- Point \( (0, 0) \)
- The line \( y = x \) intersects the horizontal axis at point \( (b, 0) \)
- The curve \( y = \frac{a}{h} x^2 \) intersects the vertical axis at point \( (0, h) \)

This shaded region is the area for which the centroid \( \bar{y} \) needs to be located.

### Instructions:

1. Use the given values: \( a = 130 \) mm, \( h = 130 \) mm, and \( b = 130 \) mm.
2. Calculate the centroid \( \bar{y} \) of the shaded area.
3. Express your answer to three significant figures and include the appropriate units.
Transcribed Image Text:### Problem Statement: Consider the area shown in (Figure 1). Suppose that: \( a = h = b = 130 \) mm **Part A:** Locate the centroid \( \bar{y} \) of the area. Express your answer to three significant figures and include the appropriate units. #### Answer Box: \[ \bar{y} = \text{Value} \, \text{Units} \] Click Submit to provide your answer. ### Figure Explanation: #### Figure 1: The graph consists of two functions plotted on the Cartesian plane: 1. **Function 1**: \( y = x \) 2. **Function 2**: \( y = \frac{a}{h} x^2 \) The enclosed area between these two curves lies between \( x = 0 \) and \( x = b \), forming a shaded region. The coordinate axes are labeled as \( x \) (horizontal axis) and \( y \) (vertical axis). The intersection of the curves with the axes are at: - Point \( (0, 0) \) - The line \( y = x \) intersects the horizontal axis at point \( (b, 0) \) - The curve \( y = \frac{a}{h} x^2 \) intersects the vertical axis at point \( (0, h) \) This shaded region is the area for which the centroid \( \bar{y} \) needs to be located. ### Instructions: 1. Use the given values: \( a = 130 \) mm, \( h = 130 \) mm, and \( b = 130 \) mm. 2. Calculate the centroid \( \bar{y} \) of the shaded area. 3. Express your answer to three significant figures and include the appropriate units.
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