**Mountain Climber Tension and Friction Analysis****Scenario:**Consider a 61.0 kg mountain climber in the figure below:- The climber is positioned on a vertical rock face, supported by a rope.- The rope is angled at 31° above the horizontal.- The climber's legs exert force at an angle of 15° below the horizontal.**Diagram Explanation:**The diagram shows a climber sitting against a vertical cliff using a rope. The forces acting on the climber include:- \( \vec{F}_{\text{legs}} \), the force exerted by the climber's legs parallel to her body.- \( \vec{T} \), the tension in the rope pulling upward at an angle.- The angle between the rope and the horizontal is 31°.- The angle between the climber’s legs and the horizontal is 15°.**Questions:****(a)** Determine the following:1. **Tension in the Rope:** - Calculate the force (in Newtons) that the rope must exert to keep the climber stationary.2. **Force on the Feet:** - Calculate the force (in Newtons) that the climber must exert with her feet on the rock face.Assumptions:- Forces by the arms are negligible.- Legs exert force parallel to the climber's body.- **Tension in Rope:** \(\_\_\_\_\_\_\_\_\) N- **Force on Feet:** \(\_\_\_\_\_\_\_\_\) N**(b)** Calculate:- **Minimum Coefficient of Friction:** - Determine the minimum coefficient of friction between the climber’s shoes and the rock to prevent slipping.- \(\_\_\_\_\_\_\_\_\_\)The above setup and calculations involve applying principles of static equilibrium, trigonometry, and friction to solve for the necessary forces and coefficients.

Answered: Image /qna-images/answer/24eb5dfe-a531-406d-a750-93894cfc3064.jpg

Consider the 61.0 kg mountain climber in the figure. 31° Flegs 15° (a) Find the tension in the rope (in N) and the force (in N) that the mountain climber must exert with her feet on the vertical rock face to remain stationary. Assume that the force is exerted parallel to her legs. Also, assume negligible force exerted by her arms. tension in rope force on feet (b) What is the minimum coefficient of friction between her shoes and the cliff?

Consider the 61.0 kg mountain climber in the figure. 31° Flegs 15° (a) Find the tension in the rope (in N) and the force (in N) that the mountain climber must exert with her feet on the vertical rock face to remain stationary. Assume that the force is exerted parallel to her legs. Also, assume negligible force exerted by her arms. tension in rope force on feet (b) What is the minimum coefficient of friction between her shoes and the cliff?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: Problem 2: Assume the surfaces are frictionless, m¡ is 5.4 kg, m2 is 10.6 kg, and the angle is 36…

A: Given quantities: m1 = 5.4 kg , m2 = 10.6 kg angle of inclination (θ) = 36 degree The force diagram…

Q: Determine the magnitude of the gripping forces exerted along line aa on the nut when two 58-lb…

A: P=58 lb

Q: C D 35.0° 77.0° 45.0 kg

Q: A 210-N mass is suspended from a horizontal beam by two cables that make angles of 29° and 53° with…

Q: 15 in. The required tension in cable AB is 200 lb. (Note: Point C is a pin joint.) D Draw a free…

Q: A street lamp weighs 180 N it is supported by two wires that form and angle of 100° with each other.…

A: Given data: - The weight of the street lamp is W = 180 N. The angle between the wire in the first…

Q: Using two ropes, Marian and Michael pull owen in a sleigh.They act at 30° to each other. Marion…

A: Marian pull by force F1=200 NMichael pull by force =F2θ=30°Resultant force R=420 N

Q: 8. Consider the 67.0 kg mountain climber. (a) Find the tension in the rope. (b) Find the force that…

Q: = 129 N = 129 N

Q: Calculate the tension in the Cable. Ꮎ = 10° Force and Tension Calculate the Tension in the cable…

Q: 5. A 210-N mass is suspended from a horizontal beam by two cables that make angles of 29° and 53⁰…

Q: An 814.5-kg mass is suspended from its body by a rope as shown in the figure and has an angle thetha…

Q: The center of mass of the arm shown in the figure is at point A. Find the magnitudes (in N) of the…

Q: Provide complete FBD and identify all the forces in it. Calculate the force P that is required to…

A: according to Newton's second law F=ma

Q: A If the length of the AB rod is 80 cm and the weight is 18N, while the weight of the load is 30N,…

Q: Э. Find the tensions in Cable C and D: C= 389 N D= 347 N Dis horizontal 27.00 D 18.0 kg

A: SOlution: Given that m = 18 kg angle = 27 degree

Q: steel 30° The agn Newtin's A Apple ♡ is centerd" at the pok Mayn + Mrue =16.0 kg

A: Given mass = 160kg θ =30° Solution T sin(30°) x 1.8 = mg x 0.9 T = 16 x 9.8 x 0.9/sin30° x 1.8 T =…

Q: A box weighing 225 N is hung from two cables. The angle between horizontal and each cable is 26.3°.…

Q: a window cleaner pushes his brush over a window vertically. the person pushes the brush at a…

A: Solution:-Given thatWeight of brush (W)=24 NCoefficient of kinetic friction (μk)=0.5Sin37°=0.6Speed…

Q: At the back of the leg, two muscles pull on the Achilles tendon to create an upward force. Estimate…

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: Disc O (weight 10 N) is supported by two frictionless planes which are perpendicular one to another.…

Q: A 143.4-N bird feeder is supported by three cables as shown in the figure below. Find the tension in…

A: Given:Weight of the bird-feeder, W = 143.4 N

Q: A sign (m. = 500 g) hangs from a horizontal beam (length L = 3m and mass mi, = 1.5 kg) as shown in…

Q: The leg and cast in the figure below weigh 266 N (w,). Determine the weight w2 and the angle a…

A: Here , A figure is given. The weight of the leg and the cast together is 266 N. We have to…

Q: A 161.0-N bird feeder is supported by three cables as shown in the figure below. Find the tension in…

A: The free body diagram is shown below.

Question

**Mountain Climber Tension and Friction Analysis**

**Scenario:**

Consider a 61.0 kg mountain climber in the figure below:

- The climber is positioned on a vertical rock face, supported by a rope.
- The rope is angled at 31° above the horizontal.
- The climber's legs exert force at an angle of 15° below the horizontal.

**Diagram Explanation:**

The diagram shows a climber sitting against a vertical cliff using a rope. The forces acting on the climber include:

- \( \vec{F}_{\text{legs}} \), the force exerted by the climber's legs parallel to her body.
- \( \vec{T} \), the tension in the rope pulling upward at an angle.
- The angle between the rope and the horizontal is 31°.
- The angle between the climber’s legs and the horizontal is 15°.

**Questions:**

**(a)** Determine the following:

1. **Tension in the Rope:**
- Calculate the force (in Newtons) that the rope must exert to keep the climber stationary.

2. **Force on the Feet:**
- Calculate the force (in Newtons) that the climber must exert with her feet on the rock face.

Assumptions:
- Forces by the arms are negligible.
- Legs exert force parallel to the climber's body.

- **Tension in Rope:** \(\_\_\_\_\_\_\_\_\) N
- **Force on Feet:** \(\_\_\_\_\_\_\_\_\) N

**(b)** Calculate:

- **Minimum Coefficient of Friction:**
- Determine the minimum coefficient of friction between the climber’s shoes and the rock to prevent slipping.

- \(\_\_\_\_\_\_\_\_\_\)

The above setup and calculations involve applying principles of static equilibrium, trigonometry, and friction to solve for the necessary forces and coefficients.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Similar questions

5. Determine the force exerted by the cable at B and the reaction at support A for the bar shown. You may assume the bar is massless for the analysis. Write your answers using 3 significant digits. y A 900 N Cable B 22° C 40° 300 mm 250 mm
A 3.0 kg box is pulled by applying a force with magnitude 8.0 N at an angle of 60⁰ above the horizontal as shown below, what are the x and y components of the force, F.
T, T 45° 60° 200 N The diagram shows a mass of force 200N held in place between two parallel vertical walls . A cable of tension T¡ at 45° above the horizontal is placed at one end and a second cable of tension T, at 60° above the horizontal is placed at the other end. The system is in equilibrium. Find the values of T, and T, (to the nearest whole numbers).
If the coefficient of static friction between all surfaces in contact is µg = 0.3 and a determine force P that must be applied to wedge A in order to lift the block weighing 500 N. The weight of wedge A is negligible compared to the block. B P
Will the 200N block shown in the figure be held in equilibrium by the force of 160N? The coefficient of static friction is 0.3. What is the actual friction force based on your calculation? P 45° Solution: A 1. There are in total 2. EF, = 0: N y 3. Fx = 0: fquired= 4. Maximum static friction fm = forces on the block, with the frictional force point to the 5. Hence the block will N; N; N; 6. The actual friction froce on the contacting surface is N
Please, explain it step-by-step process.
How do you slove?
A body with a mass M placed on a tilted surface at an angle of 0 (see figure) We applied a horizontal force F = Mg on the body as shown. a) Assume that the frictional force between the body and the surface is large so that the body remains in place. Find the FN Vertical Force and the Friction Force? b) In terms of the static coefficient of static friction oh what is the range of angle 0 at which the object remains static?
Pls help ASAP.
Needs Complete typed solution with 100 % accuracy.