Consider p(x) = 3x - 2 and q (x) = x + 7. The evaluation inner product is defined as (p, q) = p (x₁) a (x₁) +p (x2) a (x₂)+p(x3) a (x3). For (1, 2, 3) = (1, -1, 3), what is the distance d (p, q)? √179 √21
Consider p(x) = 3x - 2 and q (x) = x + 7. The evaluation inner product is defined as (p, q) = p (x₁) a (x₁) +p (x2) a (x₂)+p(x3) a (x3). For (1, 2, 3) = (1, -1, 3), what is the distance d (p, q)? √179 √21
Chapter4: Systems Of Linear Equations
Section4.6: Solve Systems Of Equations Using Determinants
Problem 279E: Explain the steps for solving a system of equations using Cramer’s rule.
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Consider p(x) = 3x - 2 and q (x) = x + 7. The evaluation inner
product is defined as
(p, q) = p (x1) a (x₁) +p (x₂) q (x₂)+p(x3) q (x3). For
(1, 2, 3) = (1, -1, 3), what is the distance d (p, q)?
O √179
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