Consider £ {y(t)} = Y(s) when solving the following equation: ty' (t) + 23ty(t) = 0 con y(0) = 0 What is Y(s)? A) Y(s) = C.e-2/23 con Cuna constante arbitraria. C B) Y(s) = 23 con C una constante arbitraria. C) Y(s) = C-e²/23 con C una constante arbitraria. D) Y(s) = C s² +23 con Cuna constante arbitraria.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Consider £ {y(t)} = Y(s)
when solving the following equation:
ty"(t) + 23ty(t) = 0 con y(0) = 0
What is Y(s)?
A) Y(s) = C.e-²/23 con C una constante arbitraria.
C
B) Y(s) =
con C una constante arbitraria.
$²-23 c
C) Y(s) = C. e¹²/23 con C una constante arbitraria.
D) Y(s) =
C
s² + 23
con Cuna constante arbitraria.
Transcribed Image Text:Consider £ {y(t)} = Y(s) when solving the following equation: ty"(t) + 23ty(t) = 0 con y(0) = 0 What is Y(s)? A) Y(s) = C.e-²/23 con C una constante arbitraria. C B) Y(s) = con C una constante arbitraria. $²-23 c C) Y(s) = C. e¹²/23 con C una constante arbitraria. D) Y(s) = C s² + 23 con Cuna constante arbitraria.
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