Consider parallelogram ABCD. A B E How can it be proven that the diagonals bisect each other? Drag tiles to the empty boxes to correctly complete each part of the proof. AB || DC because it is AB DC because opposite sides of parallelograms are congruent. ZBAC = ZDC A because they are angles. ZAEB 2 LCED because they are angles. AAEB ACED because BE = DE and AE CE because corresponding parts of congruent triangles are congruent. So, AC bisects BD and BD bisects AC because of the definition of a segment bisector. AAS ASA SAS SS given corresponding vertical alternate interior alternate exterior same-side interior

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