Consider Palmitic acid C16H32O2, a common fatty acid used in the manufacture of soap. A solution of palmitic acid is prepared by mixing 112 g palmitic acid with 725 mL of benzene C6H6. The density of the resulting solution is 0.902 g/mL. Palmitic acid (molar mass = 256 g/mol and density = 0.852 g/mL); Benzene (molar mass = 78 g/mol and density = 0.879 g/mL) What is the molarity of the solution? Final answer must be rounded off to 2 decimal places, and shall NOT have any unit. Based from the Molarity of the palmitic acid solution that you were able to solve earlier, how will you prepare 250 mL of the said molar concentration, if you have an available 2M stock solution of Palmitic acid? How many mL of the 2M palmitic acid stock solution will you need? Final answer must be rounded off to 2 decimal places, and shall NOT have any units
Consider Palmitic acid C16H32O2, a common fatty acid used in the manufacture of soap. A solution of palmitic acid is prepared by mixing 112 g palmitic acid with 725 mL of benzene C6H6. The density of the resulting solution is 0.902 g/mL. Palmitic acid (molar mass = 256 g/mol and density = 0.852 g/mL); Benzene (molar mass = 78 g/mol and density = 0.879 g/mL) What is the molarity of the solution? Final answer must be rounded off to 2 decimal places, and shall NOT have any unit. Based from the Molarity of the palmitic acid solution that you were able to solve earlier, how will you prepare 250 mL of the said molar concentration, if you have an available 2M stock solution of Palmitic acid? How many mL of the 2M palmitic acid stock solution will you need? Final answer must be rounded off to 2 decimal places, and shall NOT have any units
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter22: Organic And Biological Molecules
Section: Chapter Questions
Problem 157CP
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Consider Palmitic acid C16H32O2, a common fatty acid used in the manufacture of soap. A solution of palmitic acid is prepared by mixing 112 g palmitic acid with 725 mL of benzene C6H6. The density of the resulting solution is 0.902 g/mL.
Palmitic acid (molar mass = 256 g/mol and density = 0.852 g/mL); Benzene (molar mass = 78 g/mol and density = 0.879 g/mL)
What is the molarity of the solution?
Final answer must be rounded off to 2 decimal places, and shall NOT have any unit.
Based from the Molarity of the palmitic acid solution that you were able to solve earlier, how will you prepare 250 mL of the said molar concentration, if you have an available 2M stock solution of Palmitic acid?
How many mL of the 2M palmitic acid stock solution will you need? Final answer must be rounded off to 2 decimal places, and shall NOT have any units
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