Consider following cash flows for alternatives X and Y at an interest rate of 10% per year. Machine Initial cost, $ AOC, $/year Annual revenue, S/year Salvage value, $ Life, years X Y -146,000 -220,000 -15,000 -10,000 80,000 75,000 10,000 25,000 3 6 The capitalized cost of machine Y is closest to: $17,726 $86,590 $177,260 $207,720

Consider following cash flows for alternatives X and Y at an interest rate of 10% per year. Machine Initial cost, $ AOC, $/year Annual revenue, S/year Salvage value, $ Life, years X Y -146,000 -220,000 -15,000 -10,000 80,000 75,000 10,000 25,000 3 6 The capitalized cost of machine Y is closest to: $17,726 $86,590 $177,260 $207,720

ENGR.ECONOMIC ANALYSIS

14th Edition

ISBN:9780190931919

Author:NEWNAN

Publisher:NEWNAN

Chapter1: Making Economics Decisions

Section: Chapter Questions

Problem 1QTC

See similar textbooks

Similar questions

A manufacturing company has the choice of two suppliers to buy a piece of equipment from to use in its process. Characteristics of these two suppliers and associated costs are tabulated below. The equipment from supplier A costs more to buy and maintain, but it also has more revenue per unit sold. Selling enough units will at some point make it worth the higher cost. How many units per year must the company sell in order to justify using supplier A (i.e. what is the breakeven number of units to sell)? Use an interest rate of 12% per year. Supplier A Supplier B Initial cost $4,000 $3,000 Sale price (revenue per unit) $4 $3 Transportation costs (per unit) $0 $1.25 Annual maintenance cost $1,400 $1,100 Salvage value $800 $700 Useful life of the equipment (years) 5 4
The capitalized cost (CC) of the given project whose Cash Flow diagram is given below is closest to: = 10% per year 5 6 7 8 9 10 11 2 3 A= $2,000 PO=S30,000 C-55000 (Recurring every 5 y ears) C=55000 (Recurring every 5 years) Captalized Cost= ?
Two processes can be used for producing a polymer that reduces friction loss in engines. Process T will have a first cost of $660,000, an operating cost of $90,000 per year, and a salvage value of $80,000 after its 2-year life. Process W will have a first cost of $1,100,000, an operating cost of $25,000 per year, and a $120,000 salvage value after its 4-year life. Process W will also require updating at the end of year 2 at a cost of $90,000. Which process should be selected on the basis of a present worth analysis at a MARR of 12% per year? The present worth of process T is $- and the present worth of process W is $- The process selected on the basis of the present worth analysis is process (Click to select) ✓
Dexcon Technologies, Inc., is evaluating two alternatives to produce its new plastic filament with low friction properties for creating custom bearings for 3-D printers. The estimates associated with each alternative are shown below. Using a MARR of 16% per year, which alternative has the better present worth and what is that value (select the closest value)? Method First Cost AOC, per Year Salvage Value Life DDM $170,000 $65,000 $4,000 2 years LS $350,000 $40,000 $29,000 4 years DDM with a PW--$473,000 LS with a PW --$445,900 LS with a PW --$222,055 DDM with a PW--$109,300
Give typing answer with explanation and conclusion
A professional mechanics who specializes in truck engines paid $46,000 for equipment that will have a $4800 salvage value after 5 years. The costs with each usage amount to $60 per day. The income is $290 per day for his services, how many days per year must he be worked in order to break even at an interest rate of 7% per year?
An IE works in the automation department of a surgical equipment manufacturing company that produces specially ordered equipment for hospitals. To upgrade the quality of the assembly process of the camera used in laparoscopic surgery probes, two approaches are available: make and buy. The make alternative has an initial equipment cost of $175,000, a life of 5 years, a $25,000 salvage value, a processing cost of $3,000 per camera, and an M&O cost of $90,000. The buy alternative requires contracting the assembly operation externally at a cost of $7,250 per camera. If the MARR is 12% per year, how many cameras per year must be assembled to justify the make alternative? 27 cameras must be assembled per year to justify the make alternative.
The cost of the extending a certain road at Yellowstone National Park is $1.7 million. Resurfacing and other maintenance are expected to cost $350,000 every 3 years with an interest rate of 6% per year. a) What is the Annual Worth based capitalized cost of the road? b) How will the answer (a) change if its Salvage is expected to be $3 million at the end of its useful Life?
1. The annual worth for years 1 through infinity of $75,000 now, $25,000 per year in years 1 through 15 and S40,000 per year in years 16 through infinity at a 10% interest per year is closest to: (a) $27,500 (b) $36,000 (c) $44,000 (d) $ 19,500 1. For the estimates in table below, calculate the equivalent annual cost of the project: First Cost, $ -950,000 Replacement Cost, year 2 AOC, $/ year Salvage value, $ -450,000 -600,000 175,000 Life, years 4 Interst Rate % 10
Whole solution
Answer it correctly please. I will rate accordingly
A newly proposed project has a first cost of $ 211962 and estimated annual income of $46410 per year for 10 years. Determine the PW value if the MARR is 10.4% per year.