Consider carbon allotropes diamond and graphite. Unlike diamond, graphite conducts electricity. Why? 1. In graphite, there are hybrid orbitals used for bonding that contain electrons. 2. In diamond, all the electrons are in sigma bonds which allow conductivity of electricity. 3. In graphite, there are unhybridized p- orbitals that extend over the entire sheet forming a delocalized pi (1) bonding network where electrons are free to move. 4. In diamond, the bonding electrons have enough energy to move and can therefore conduct electricity. 5. In graphite, the bonds are 109°, which is perfect for electricity conduction.
Consider carbon allotropes diamond and graphite. Unlike diamond, graphite conducts electricity. Why? 1. In graphite, there are hybrid orbitals used for bonding that contain electrons. 2. In diamond, all the electrons are in sigma bonds which allow conductivity of electricity. 3. In graphite, there are unhybridized p- orbitals that extend over the entire sheet forming a delocalized pi (1) bonding network where electrons are free to move. 4. In diamond, the bonding electrons have enough energy to move and can therefore conduct electricity. 5. In graphite, the bonds are 109°, which is perfect for electricity conduction.
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter7: Chemical Bonding And Molecular Structure
Section: Chapter Questions
Problem 7.72PAE: 7.72 How does an MSN differ from amorphous silica so that is has improved biocompatibility?
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![### Understanding Electrical Conductivity in Carbon Allotropes: Diamond and Graphite
**Consider carbon allotropes diamond and graphite. Unlike diamond, graphite conducts electricity. Why?**
1. **In graphite, there are hybrid orbitals used for bonding that contain electrons.**
2. **In diamond, all the electrons are in sigma bonds which allow conductivity of electricity.**
3. **In graphite, there are unhybridized p-orbitals that extend over the entire sheet forming a delocalized pi (π) bonding network where electrons are free to move.**
4. **In diamond, the bonding electrons have enough energy to move and can therefore conduct electricity.**
5. **In graphite, the bonds are 109°, which is perfect for electricity conduction.**
#### Multiple-Choice Question:
Which statement(s) correctly explains why graphite conducts electricity but diamond does not? Select the correct answer.
- [ ] 2
- [ ] 3
- [ ] 5
- [ ] 4
- [ ] 1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faf6c3174-f071-4892-a981-9c51afb6153d%2F876618e2-dc08-4131-a91c-ccccfcded0fb%2Fwcw1k4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Understanding Electrical Conductivity in Carbon Allotropes: Diamond and Graphite
**Consider carbon allotropes diamond and graphite. Unlike diamond, graphite conducts electricity. Why?**
1. **In graphite, there are hybrid orbitals used for bonding that contain electrons.**
2. **In diamond, all the electrons are in sigma bonds which allow conductivity of electricity.**
3. **In graphite, there are unhybridized p-orbitals that extend over the entire sheet forming a delocalized pi (π) bonding network where electrons are free to move.**
4. **In diamond, the bonding electrons have enough energy to move and can therefore conduct electricity.**
5. **In graphite, the bonds are 109°, which is perfect for electricity conduction.**
#### Multiple-Choice Question:
Which statement(s) correctly explains why graphite conducts electricity but diamond does not? Select the correct answer.
- [ ] 2
- [ ] 3
- [ ] 5
- [ ] 4
- [ ] 1
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