Consider an isosceles triangle (shown in blue) whose bottom base is 10 units long. A rectangle (shown in red) is inscribed inside the triangle as shown in the figure below: What are the dimensions of such a rectangle with the greatest possible Area? Hint: Let x be the first coordinate of the point (x,y) shown, and find an equation of the blue line/side of the triangle. Give an equation for the Area of the Rectangle as a function of z. Area A = Optimal Solution: Width - Height = and the Maximal Area is

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Consider an isosceles triangle (shown in blue) whose bottom base is 10 units long. A rectangle (shown in red) is inscribed inside the triangle as shown in the figure below:

[Graph Description]
- The x-axis ranges from -6 to 6, and the y-axis ranges from 0 to 9.
- The blue isosceles triangle has a base along the x-axis, spanning from -5 to 5.
- The triangle reaches a peak at (0, 9).
- A red rectangle is inscribed inside the triangle, with its base on the x-axis.
- The top right corner of the rectangle is labeled as (x, y).

What are the dimensions of such a rectangle with the greatest possible area?

Hint: Let \( x \) be the first coordinate of the point \((x, y)\) shown, and find an equation of the blue line/side of the triangle.

Give an equation for the Area of the Rectangle as a function of \( x \).

Area \( A = \)

Optimal Solution:
Width = \(\quad\),
Height = \(\quad\),

and the Maximal Area is \(\quad\).

[Note: The solution involves calculus and finding the maximum area of the rectangle using optimization techniques.]
Transcribed Image Text:Consider an isosceles triangle (shown in blue) whose bottom base is 10 units long. A rectangle (shown in red) is inscribed inside the triangle as shown in the figure below: [Graph Description] - The x-axis ranges from -6 to 6, and the y-axis ranges from 0 to 9. - The blue isosceles triangle has a base along the x-axis, spanning from -5 to 5. - The triangle reaches a peak at (0, 9). - A red rectangle is inscribed inside the triangle, with its base on the x-axis. - The top right corner of the rectangle is labeled as (x, y). What are the dimensions of such a rectangle with the greatest possible area? Hint: Let \( x \) be the first coordinate of the point \((x, y)\) shown, and find an equation of the blue line/side of the triangle. Give an equation for the Area of the Rectangle as a function of \( x \). Area \( A = \) Optimal Solution: Width = \(\quad\), Height = \(\quad\), and the Maximal Area is \(\quad\). [Note: The solution involves calculus and finding the maximum area of the rectangle using optimization techniques.]
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