Consider an insulating solid sphere of radius a with a uniform volume charge density, ρ < 0, is placed concentric with an insulating spherical shell, of inner radius a and outer radius b, with a uniform charge density ρ > 0. Calculate the electric field at a distance r from the common center of the two spheres for a) 0b. The image below shows the possible answers for each item.
Consider an insulating solid sphere of radius a with a uniform volume charge density, ρ < 0, is placed concentric with an insulating spherical shell, of inner radius a and outer radius b, with a uniform charge density ρ > 0. Calculate the electric field at a distance r from the common center of the two spheres for a) 0b. The image below shows the possible answers for each item.
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter16: Temperature And The Kinetic Theory Of Gases
Section: Chapter Questions
Problem 9P
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Question
Consider an insulating solid sphere of radius a with a uniform volume charge density, ρ < 0, is placed concentric with an insulating spherical shell, of inner radius a and outer radius b, with a uniform charge density ρ > 0. Calculate the electric field at a distance r from the common center of the two spheres for a) 0<r<a, b) a<r<b, and c) r>b.
The image below shows the possible answers for each item.
![Choices for (a):
Choices for (b):
А. О
p(r³ –2a³)
3r2 ɛo
A. Ε=
pr
В.Е -
3Ɛo
В. Е —
P(r³-a³)
3r2 ɛo
C.E =
pr
%3D
3εο
C. E = P(2a³+r3)
3r2 ɛo
ра
D.E =
3ɛo
С. Е —
ра
Е. Е —
D. E = P(2a³-r3)
3r2ɛo
3ɛo
p(a³+r³)
3r² ɛo
E. E =
%3D
Choices for (c):
А.О
В.Е:
pr
3εο
P(2a³+b³)
3r2 ɛo
С.Е
D.E = P(2a³-b³)
3r2 ɛo
E. E = P(b³-2a³)
3r2ɛo](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe624db12-d092-466d-88b6-51e01cb47283%2Fa6522aaf-45dd-4654-8b93-2bb017860f04%2Fx4nerva_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Choices for (a):
Choices for (b):
А. О
p(r³ –2a³)
3r2 ɛo
A. Ε=
pr
В.Е -
3Ɛo
В. Е —
P(r³-a³)
3r2 ɛo
C.E =
pr
%3D
3εο
C. E = P(2a³+r3)
3r2 ɛo
ра
D.E =
3ɛo
С. Е —
ра
Е. Е —
D. E = P(2a³-r3)
3r2ɛo
3ɛo
p(a³+r³)
3r² ɛo
E. E =
%3D
Choices for (c):
А.О
В.Е:
pr
3εο
P(2a³+b³)
3r2 ɛo
С.Е
D.E = P(2a³-b³)
3r2 ɛo
E. E = P(b³-2a³)
3r2ɛo
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