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Consider an Information system, a a frame size of (5 million) bits are being sent on a path with (10 routers) each having a queuing time of (2 µs) and a processing time of (1 µs). The length of the path is (2000 Km). Acknowledgement frame size is (1 bytes) and the speed of light inside the link is (2*10^8 m/s). Every link on the path has a bandwidth of (5 Mbps), then the total delay (latency) for this frame is............. 0.000016 sec. 0.000020 sec. O 0.000010 sec. O 1.020046 sec. O 0.01 sec.

Consider an Information system, a a frame size of (5 million) bits are being sent on a path with (10 routers) each having a queuing time of (2 µs) and a processing time of (1 µs). The length of the path is (2000 Km). Acknowledgement frame size is (1 bytes) and the speed of light inside the link is (2*10^8 m/s). Every link on the path has a bandwidth of (5 Mbps), then the total delay (latency) for this frame is............. 0.000016 sec. 0.000020 sec. O 0.000010 sec. O 1.020046 sec. O 0.01 sec.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Consider an Information system, of a frame size of (5 million) bits are being sent on a path with (10 routers) each having a queuing time of (2 µs) and a processing time of (1 µs). The length of the path is (2000 Km). Acknowledgement frame size is (10 bytes) and the speed of light inside the link is (2 *10^8 m/s). Every link on the path has a bandwidth of (5 Mbps), then the total delay (latency) for this frame is........... O 0.000016 sec. O 0.000020 sec. O 0.000010 sec. O 1.020046 sec. O 0.01 sec.
Transcribed Image Text:Consider an Information system, of a frame size of (5 million) bits are being sent on a path with (10 routers) each having a queuing time of (2 µs) and a processing time of (1 µs). The length of the path is (2000 Km). Acknowledgement frame size is (10 bytes) and the speed of light inside the link is (2 *10^8 m/s). Every link on the path has a bandwidth of (5 Mbps), then the total delay (latency) for this frame is........... O 0.000016 sec. O 0.000020 sec. O 0.000010 sec. O 1.020046 sec. O 0.01 sec.
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