Consider an infinitely long wire of charge carrying a positive charge density of A. The electric field due to this line of charge is given by E= 2ke=r= -, where is a unit vector directed radially outward 2περ r from the infinitely long wire of charge. Hint a. Letting the voltage be zero at some reference distance (V(ro) = 0), calculate the voltage due to this infinite line of charge at some distance r from the line of charge. Give your answer in terms of given quantities (A,ro,r) and physical constants (ke or so). Use underscore ("_") for subscripts and spell out Greek letters. Hint for V(r) calculation V(r) b. There is a reason we are not setting V(ro) = 0 as we normally do (in fact, in general, whenever you have an infinite charge distribution, this "universal reference" does not work; you need a localized charge distribution for this reference to work). Which of the following best describes what happens to potential as roo? (That is, what is V(r- →∞), with our current reference, V(ro) = 0?) OV(ro) asymptotically approaches a finite value. OV(ro) oscillates within a bounded range (no well-defined limit but does not diverge). OV(r) decreases to - without limit. OV(ro) increases to +∞ without limit.

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Consider an infinitely long wire of charge carrying a positive charge density of A. The electric field due to
X
-, where is a unit vector directed radially outward
r 2περ
this line of charge is given by E = 2ke - =
from the infinitely long wire of charge.
Hint
a. Letting the voltage be zero at some reference distance (V(ro) = 0), calculate the voltage due to
this infinite line of charge at some distance r from the line of charge. Give your answer in terms of
given quantities (A,ro,r) and physical constants (ke or so). Use underscore ("_") for subscripts and
spell out Greek letters.
Hint for V(r) calculation
V(r):
b. There is a reason we are not setting V(r → ∞) = 0 as we normally do (in fact, in general,
whenever you have an infinite charge distribution, this "universal reference" does not work; you need
a localized charge distribution for this reference to work).
Which of the following best describes what happens to potential as r → ∞? (That is, what is
V(r → ∞), with our current reference, V(ro) = 0?)
OV(r → ∞) asymptotically approaches a finite value.
OV(ro) oscillates within a bounded range (no well-defined limit but does not diverge).
O V(ro) decreases to - without limit.
OV(r-
→∞)
to +∞o without limit.
Transcribed Image Text:Consider an infinitely long wire of charge carrying a positive charge density of A. The electric field due to X -, where is a unit vector directed radially outward r 2περ this line of charge is given by E = 2ke - = from the infinitely long wire of charge. Hint a. Letting the voltage be zero at some reference distance (V(ro) = 0), calculate the voltage due to this infinite line of charge at some distance r from the line of charge. Give your answer in terms of given quantities (A,ro,r) and physical constants (ke or so). Use underscore ("_") for subscripts and spell out Greek letters. Hint for V(r) calculation V(r): b. There is a reason we are not setting V(r → ∞) = 0 as we normally do (in fact, in general, whenever you have an infinite charge distribution, this "universal reference" does not work; you need a localized charge distribution for this reference to work). Which of the following best describes what happens to potential as r → ∞? (That is, what is V(r → ∞), with our current reference, V(ro) = 0?) OV(r → ∞) asymptotically approaches a finite value. OV(ro) oscillates within a bounded range (no well-defined limit but does not diverge). O V(ro) decreases to - without limit. OV(r- →∞) to +∞o without limit.
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